Problem 6.17 A torsion member has and elliptical cross section with major and minor dimensions of 50.0 mm and30.0 mm, respectively. The yield stress of the material in the torsion member is Y=400 MPa.Determine the maximum torque that can be applied to the torsion member based on a factor of safety ofSF=1.85 using the maximum shear stress criterion of failure.Solution:h30 mm⋅215 mm⋅=:=b50 mm⋅225 mm⋅=:=Y400 MPa⋅:=SF1.85:=τmax2T⋅πb⋅h2⋅=Eq. 6.47, page 215All other stresses are zero.SFY2τmax=Y2⋅π
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This note was uploaded on 01/11/2011 for the course MAE 3040 taught by Professor Mechanicsofsolids during the Spring '10 term at Utah State University.