Problem_06_17 - Problem 6.17 A torsion member has and...

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Problem 6.17 A torsion member has and elliptical cross section with major and minor dimensions of 50.0 mm and 30.0 mm, respectively. The yield stress of the material in the torsion member is Y=400 MPa. Determine the maximum torque that can be applied to the torsion member based on a factor of safety of SF=1.85 using the maximum shear stress criterion of failure. Solution: h 30 mm 2 15 mm = := b 50 mm 2 25 mm = := Y 400 MPa := SF 1.85 := τ max 2T π b h 2 = Eq. 6.47, page 215 All other stresses are zero. SF Y 2 τ max = Y 2 π
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This note was uploaded on 01/11/2011 for the course MAE 3040 taught by Professor Mechanicsofsolids during the Spring '10 term at Utah State University.

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