Problem_06_31 - Problem 6.31 A steel bar has a rectangular...

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Problem 6.31 A steel bar has a rectangular cross setion 12.7 mm wide and 38.1 mm deep. The bar is subjected to a twisting moment T =135.7 N-m. The shear yield stress of the material is 82.7 MPa. (a) By Eq. 6.64, calculate the maximum shear stress in the bar and show in a diagram where it occurs. (b) Calculate the shear stress in the bar at the center of the short side. Solution: Location of τ max (a) τ max T k 2 2b () 2h 2 = Eq. 6.64 T 135.7 N m := h 12.7 mm 2 := b 38.1 mm 2 := b h 3 = From Table 6.1, page 225 k 1 0.263 := k 2 0.267 := τ max T k 2 2 82.706 MPa = := (b) To obtain the shear stress at the center of the short side, interchange (2b) and (2h) in Eq. 6.64)
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This note was uploaded on 01/11/2011 for the course MAE 3040 taught by Professor Mechanicsofsolids during the Spring '10 term at Utah State University.

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