Problem 6.31 A steel bar has a rectangular cross setion 12.7 mm wide and 38.1 mm deep. The bar is subjected to atwisting moment T=135.7 N-m. The shear yield stress of the material is 82.7 MPa. (a) By Eq. 6.64, calculate the maximum shear stress in the bar and show in a diagram where it occurs.(b) Calculate the shear stress in the bar at the center of the short side.Solution:Location of τmax(a)τmaxTk22b⋅()⋅2h⋅2⋅=Eq. 6.64T135.7 N⋅m⋅:=h12.7 mm⋅2:=b38.1 mm⋅2:=bh3=From Table 6.1, page 225k10.263:=k20.267:=τmaxTk2⋅⋅⋅2⋅82.706 MPa=:=(b) To obtain the shear stress at the center of the short side,interchange (2b) and (2h) in Eq. 6.64)
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This note was uploaded on 01/11/2011 for the course MAE 3040 taught by Professor Mechanicsofsolids during the Spring '10 term at Utah State University.