Problem_08_11 - L 1 l t l ⋅ L 1 ⋅ ⌠ ⎮ ⌡ d ⋅...

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Problem 8.11 Find the shear center for the cross section Solution: Let V1 N := t3 m m := L 1 30 mm := L 2 60 mm := L 3 20 mm := Summation of moments about O yields: Ve F 1 L 1 2 F 3 L 3 2 = I x tL 2 () 3 12 2t L 1 L 1 () 2 + 2t L 1 L 3 () 2 + 2.88 10 7 × m 4 = := F 1 V I x 0mm
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Unformatted text preview: L 1 l t l ⋅ L 1 ⋅ ⌠ ⎮ ⌡ d ⋅ 0.141 N = := F 3 V I x 0 mm ⋅ L 1 l t l ⋅ L 3 ⋅ ⌠ ⎮ ⌡ d ⋅ 0.094 N = := e F 1 V L 1 ⋅ 2 ⋅ F 3 V L 3 ⋅ 2 ⋅ − 4.687 mm = :=...
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This note was uploaded on 01/11/2011 for the course MAE 3040 taught by Professor Mechanicsofsolids during the Spring '10 term at Utah State University.

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