80 mm Do= ? Problem 11.19Given: A closed cylinder is made of a ductile steel that has ayield stress Y = 600 MPa. The inside diameter of the cylinderis 80 mm. Determine the outside diameter of the cylinder if thecylinder is subjected to an internal pressure of p1= 140 MPaand the cylinder is designed using a factor of safety of SF =1.75 based on the maximum shear-stress criterion of failure.Solution:a80 mm⋅2:=p1140 MPa⋅:=p20 MPa⋅:=P0:=SF1.75:=Y600 MPa⋅:=Using Eq. 11.20 at at r=a gives:σrrp1−140−MPa⋅=:=Assume thatσrrσzz<σθθ<so thatSFY2σθθσrr−2⎛⎜⎝⎞⎟⎠=Yσθθσrr−()=Thus: σθθYSFσ
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