Problem_15_06 - t and a = 6.7 mm Since a>6.7mm and...

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Problem 15. 6 Given: A long strip of aluminum alloy 2024-T851 has a width of 150 mm and thickness of 8.0 mm. An edge crack of length a = 9.0 mm (Case 4 of Table 15.2) is located at one edge of the strip near the center of its length. Find: the magnitude of the axial load P that will cause brittle fracture. Solution: a9 m m := c 150 mm := t8 m m := From Table 15.1 K IC 23 MPa m
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Unformatted text preview: t and a = 6.7 mm Since a >6.7mm and t >6.7, crack can propagate if the stress is high enough. λ a c 0.06 = := f λ ( ) 1.12 1.37 1.12 − ( ) λ 0.2 ⋅ + := f λ ( ) 1.195 = From Table 15.2 K I σ π a ⋅ f λ ( ) ⋅ = At failure K I K IC := σ K IC π a ⋅ f λ ( ) ⋅ 114.463MPa ⋅ = := P σ t ⋅ c ⋅ 137.355kN ⋅ = :=...
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This note was uploaded on 01/11/2011 for the course MAE 3040 taught by Professor Mechanicsofsolids during the Spring '10 term at Utah State University.

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