{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Lab_Report5

# Lab_Report5 - one without the ring on the disk and one with...

This preview shows pages 1–2. Sign up to view the full content.

Lab Report #5 - Moment of inertia of a complex system Statement of the Problem The problem was to determine the moment of inertia of the following system: We fastened a metal ring to the top of a heavy, solid disk, a “flywheel”, and that disk is attached to a shaft. Below the disk there is a metal spool on the shaft to wind string around. A ring sits on the disk so both ring and disk share the same rotational axis. A length of string is wrapped around the spool and then passes over a pulley lined up with the tangent to the spool. A weight is hung from the other end of the string so that the weight can fall past the edge of the table. As the hanging weight falls, the string pulls on the spool, causing the system to rotate. This time we made manual measurements with a stopwatch. We measured the time it takes the hanging mass get from a specific height to the floor. We made two experiments:

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: one without the ring on the disk and one with the ring on the disk. Predictions Our group predicted that the moment of inertia for the experiment with the ring on the disk will be larger than the moment of inertia for the experiment without the ring on the disk. We have observed, than when there is a ring on the disk, the mass goes down slower. Mathematically, we start from the equation of angular acceleration: α r a m = r m a a = Moment of inertia of the system: ) 2 1 ( 2 2 2 1 1 R M R M I + = Energy conservation: mgh E = 1 2 2 2 2 1 2 1 Iw mv E + = I mr mg w + = 2 2 π 2 2 2 t w f = = w T π 2 = Experiment and results: Mass is released from h= 0.33 m Trial 1 Trial 2 m 1= 1500 g t 1 =3.18s+-0.01s m 1= 1500 g+-10g m 2= 1500 g+-10g t 1 =3.61s+-0.01s m m R 01 . 61 . 2 ± = r = (9.5*(10^-4) m )+-(1*10^-4) R 1 = 0.115 m +-0.005 m...
View Full Document

{[ snackBarMessage ]}