labreport1 - Movement of on object released from rest down...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Movement of on object released from rest down an incline Statement of the problem: The problem was to determine the dependence of acceleration of an object on its initial velocity. We rolled a car down a wood ramp, once from rest and once with an initial velocity. We made 2 movies with the video equipment provided, once for the car rolled from rest, and once with an initial velocity. These movies were analyzed with LabVIEW to study the dependence of the initial velocity on the acceleration. Prediction Our group predicted that the acceleration will remain the same in both of the experiments. We have observed that the time it takes to the car released from rest to get to the bottom of the ramp is larger than the time it takes to the car with the initial velocity to get to the bottom of the ramp. Since the gravitational acceleration is constant, we reasoned that the acceleration will be the same. Mathematically, we start from the relationship between position, time and velocity: 0 x is the initial x position of the car, 0 v is the initial velocity of the car, a is the acceleration (1) 2 0 0 1 2 x x v t at = + + With the x- axis in the downward direction of the ramp, and the y- axis vertical to the ramp’s surface, and the positive direction down (see graph a), we know the acceleration in the y- axis is: (2) a y =0 And the acceleration in the x- axis is: (3) a x = sin g θ (a) Motion equation in the x- axis for an object released without initial velocity ( 0 v =0): (4) 2 1 sin 2 x g t θ = θ y x
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern