Ch5_D_Solutions

100 m then na 0200 m co32 0100 m step 2 calculate

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Unformatted text preview: [Na2CO3] = 0.100 M, then [Na+] = 0.200 M [CO32-] = 0.100 M Step 2: Calculate molarity 0.0210 mol = 0 .0841 M 0.250 L [NiCl2•6 H2O ] = 0.0841 M NiCl KMnO4(aq) --> K+(aq) + MnO4-(aq) aq) aq) aq) If [KMnO4 ] = 0.30 M, then [K+] = [MnO 4-] = 0.30 M Page 1 USING MOLARITY USING MOLARITY What mass of oxalic acid, H 2C2O4, is required to make 250. mL of a 0.0500 M solution? Because Conc (M) = moles/volume = mol/V mol/V this means that USING MOLARITY USING MOLARITY What mass of oxalic acid, H2C2O4, is required to make 250. mL of a 0.0500 M solution? Preparing Solutions Preparing Solutions • Weigh out a solid solute and dissolve in a given quantity of solvent. • Dilute a concentrated solution to give one that is less concentrated. moles = M • V Step 1: Calculate moles of acid required. (0.0500 mol/L)(0.250 L) = 0.0125 mol mol/L)(0.250 Step 2: Calculate mass of acid required. (0.0125 mol )(90.00 g/mol) = g/m...
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This note was uploaded on 01/11/2011 for the course ENGINEERIN MAE 107 taught by Professor Pozikrizdis during the Fall '08 term at San Diego.

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