Chapter3Lecture

Chapter3Lecture - Chapter 3 Finding an Empirical Formula...

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6 Chapter 3: Finding an Empirical Formula More difficult is finding the compound when knowing the masses or percentages. If given percentages, just assume 100 g total. Given: 43.40% Na or 43.40 g 11.32% C 11.32 g 45.28% O 45.28 g Therefore: Na 1.888 C 0.9433 O 2.830 We must have integers. All seem to be a bit low. So: Na 2 C O 3 or Na 2 (CO 3 ) We have sodium carbonate. Copyright: 2010 Prof. Magde 1 mole Na 43.40 g Na 1.888mole Na 22.99 g Na 1moleC 11.32 g C 0.9433 mole C 12.01gC 1 mole O 45.28 g O 2.830 mole O 16.00gO
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1moleFe 8.377g Fe 0.1500 moleFe 55.847g Fe 1moleO 3.600gO 0.2250 moleO 16.00gO
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