9-28-10 - Lecture 2 - Chapter2

9-28-10 - Lecture 2 - Chapter2 - Law of Mass Conservation...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
In a Chemical Reaction : The number of substances may change and their properties will change but the total amount of matter remains constant. reactant 1 + reactant 2 product total mass total mass = calcium oxide + carbon dioxide calcium carbonate CaO + CO 2 CaCO 3 56.08 g + 44.01 g 100.09 g (Symbols) (Words) (Quantities) Law of Mass Conservation
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Law of Definite Composition No matter the source, a particular compound is composed of the same elements in the same parts (fractions) by mass. Calcium carbonate, CaCO 3 Analysis by Mass Analysis by Mass (grams/20.0 g) (grams/20.0 g) Mass Fraction Mass Fraction (parts/1.00 part) (parts/1.00 part) Percent by Mass Percent by Mass (parts/100 parts) (parts/100 parts) 8.0 g calcium 8.0 g calcium 2.4 g carbon 2.4 g carbon 9.6 g oxygen 9.6 g oxygen 20.0 g 20.0 g 40% calcium 40% calcium 12% carbon 12% carbon 48% oxygen 48% oxygen 100% by mass 100% by mass 0.40 calcium 0.40 calcium 0.12 carbon 0.12 carbon 0.48 oxygen 0.48 oxygen 1.00 part by mass Figure 2.2
Image of page 2
If elements A and B react to form two compounds, the different
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern