Pset3 Solution

# Pset3 Solution - 1. 2 2 2003 . 4 in d A = = π , psi A F a...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1. 2 2 2003 . 4 in d A = = π , psi A F a a 3 10 02 . 36 × = = σ psi E a a 6 10 96 . 21 × = = ε σ , 296 . = − = a L ε ε ν 2. lbf in M ⋅ = × = 500 10 50 . psi wt M I My 3556 75 . 5 . 1 500 6 6 2 2 = × × = = = σ strain E − = = µ σ ε 7 . 119 1 1 2 νε ε − = Since the two gages are in adjacent arms, ε ν ε ε 4 ) 1 ( | | 4 | | 2 1 F F e e i o + = − = ∆ 67 . 1 ) 1 ( 4 = + ∆ = ε ν i o e e F 3. (a) For the rectangular rosette, we have y c xy y x o x b x a ε ε γ ε ε θ ε ε ε ε = + + = = = = 2 2 ) 45 ( ' therefore 60 2 680 320 = − − = = = − = = y x b xy c y a x ε ε ε γ ε ε ε ε in µ-strain (b) Solving ) ( 1 ) ( 1 x y y y x x E E νσ σ ε νσ σ ε − = − = we get psi E psi E psi E xy xy x y y y x x 232 ) 1 ( 2 6411 ) ( 1 1340 ) ( 1 2 2 = + = = + − = − = + − = γ ν τ νε ε ν σ νε ε ν σ (c) psi psi xy y x y x 1347 6418 3882 2536 ) 2 ( 2 2 1 2 2 2 , 1 − = = ± = + − ± + = σ σ τ σ σ σ σ σ 4. Based on the rectangular rosette reading, we can find 4....
View Full Document

## This note was uploaded on 01/12/2011 for the course MAE 3800 taught by Professor Feng during the Spring '10 term at Missouri (Mizzou).

### Page1 / 3

Pset3 Solution - 1. 2 2 2003 . 4 in d A = = π , psi A F a...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online