{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW#1 - K-Cl pair and r is the distance innanometers The net...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
HomeWork 1 Class:EGN 3365 Prof : Dr. Seal TA: Himesh Bhatt Submission Date: Tuesday, 1 Sept 2003 Problem 1 Without consulting Figure 2.6 or Table 2.2, determine whether each of the electron configurations given below is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. Justify your choices. (a) 1s 2 2s 2 2p 6 3s 2 3p 6 3d 7 4s 2 (b) 1s 2 2s 2 2p 6 3s 2 3p 6 (c) 1s 2 2s 2 2p 5 (d) 1s 2 2s 2 2p 6 3s 2 (e) 1s 2 2s 2 2p 6 3s 3 3p 6 3d 2 4s 2 (f) 1s 2 2s 2 2p 6 3s 2 3p 6 4s 1 Problem 2 For a K + -Cl - ion pair, attractive and repulsive energies E A and E R , respectively, depend on the distance between the ions r, according to E A = -1.436 r E A = 5.86 X 10 -6 r 9 For these expressions, energies are expressed in electron volts per
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: K +-Cl- pair, and r is the distance innanometers. The net energy E N is just the sum of the two expressions above. (a) Superimpose on a single plot E N , E R , and E A versus r up to 1.0nm. (b) On the basis of this plot, determine (i)the equilibrium spacing r between the K + and Cl + (c) Ions and (ii) the magnitude of the bonding energy E between the two ions. Problem 3 Explain why hydrogen fluoride (HF) has a higher boiling temperature than hydrogen chloride (HCL) (19.4 vs. -85 ° C), even though HF has a lower molecular weight....
View Full Document

{[ snackBarMessage ]}