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Unformatted text preview: without plastic deformation ( F y ). Taking the yield strength to be 275 MPa, and employment of Equation (6.1) leads to F y = σ y A o = (345 x 10 6 N/m 2 )(130 x 10-6 m 2 ) = 44,850 N (b) The maximum length to which the sample may be deformed without plastic deformation is determined from Equations (6.2) and (6.5) as l i = l o = (76 mm) + MPa x MPa 3 10 103 345 1 = 76.254 mm Or ∆ l = l i- l o = 76.254 mm - 76.00 mm = 0.254 mm...
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This note was uploaded on 01/13/2011 for the course EGN 3365 taught by Professor Yong-hosohn during the Spring '08 term at University of Central Florida.
- Spring '08