physics2 - In the case of part 1, the two dipoles caused by...

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The electric field is simply the electric force exerted by a test charge q divided by the magnitude of the test charge. E field =r =kq /r 2 r (2) Where q’ represents the charge emanating from a source, and q is the charge of the test particle, k= coulomb’s constant, r= the distance at which the electric field is applies. Both the electric field and the force due to the electric field are vector quantities, so r represents the vector.
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Unformatted text preview: In the case of part 1, the two dipoles caused by the two electrodes placed along the x-axis distorts the relationship between voltage and the distance between the electrodes such that: V=kQ[1/|a-x|-1/|a+x|] (8) Where x is the displacement between the probe of the electrode and the probe on the multimeter, Q is the sum of the charges from the two electrodes and a is the displacement of one electrode to the origin at (0,0)....
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This note was uploaded on 01/13/2011 for the course PHY 103M taught by Professor Staff during the Fall '08 term at University of Texas.

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