3765.Χdof( chi degree of freedom)= (SD)2where SD refers to the standard deviation of the dataSo in the case of the two parallel plates, SD= 3.06 . Therefore, Χdof =(SD)2=(3.06)2= 9.3765Because this number was lower than the result obtained in the case of the two dipoles, I believe this number is reasonable. One reason this number is lower is that the data in the parallel plates
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