Newtons - Which is shown on the graph above. The slope of...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Adam J. Englert October 8, 2008 Newton’s 2 nd Law 8:30 – 10:20 Lab partners: Unsure of their names
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
The purpose of this experiment is to test Newton’s Second Law of Motion, ∑F = ma. We will set up a system in which we hold m constant and vary F. The equipment used on this experiment are as follows: an air track glider, two pulleys, a set of weights, two weight hangers and a computerized data acquisition system. m1 m2 a (m2- m1)*g 160 170 0 98 Slope Intercept 155 175 0.057 196 Theory 308.5g 98 150 180 0.363 294 Linest 433.5962 140.5069 145 185 0.493 392 56.66726 26.73009 140 190 0.857 490 113.3345 53.46017 Agreement Yes Yes The plot is a straight line when I plotted the (m2-m1)*g versus a using Excel.
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Which is shown on the graph above. The slope of the line would be 433.6, while the intercept is 140.5. So that concludes that it is not equal to the mass of the glider. But it is relatively close to the correct slope range. It is off by about twelve. The slop decreases dramatically if you use the ∑F= sqrt(2)*ma. So that definitely is not the correct form for Newton’s 2 nd Law. In conclusion, my experiment did indeed confirm Newton’s 2 nd Law of ∑F = ma....
View Full Document

This note was uploaded on 01/13/2011 for the course BUS A202 taught by Professor Tindall during the Spring '10 term at IUPUI.

Page1 / 2

Newtons - Which is shown on the graph above. The slope of...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online