Static Equilibrium

Static Equilibrium - grams, or 341.5grams. Then we solved...

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Adam J. Englert November 19, 2008 Static Equilibrium 8:30 – 10:20 Lab partners: (None)
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The purpose of this experiment is to study the conditions for a two-dimensional rigid body to be in equilibrium by direct measurement of the forces involved. The equipment that I used in this experiment was a static equilibrium board and bar, one 200 grams hanging weight, a set of slotted weights and three weight hangers. The rigid bar, which weights 283 grams, is originally attached to the board by removable pins. The pins provide forces which satisfy the equilibrium conditions. Once we equate the correct weight to hang on all of the hangers the bar should stay in the original position after the pins are removed. Our theoretical values for T, H, and V Once we solved the equation T={[(mg)/2]cosα+kcosв}/sin(в+α), where в = 30° and α = 30°. We found that the T value as a force was 3.3467N, which then had to be converted to
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Unformatted text preview: grams, or 341.5grams. Then we solved the equation H=Tcos. We found that the H value as a force was 2.898N, which then had to be converted to grams, or 295.7grams. Finally we solved the equation V=mg+k-Tsin. We found the V value as a force was 3.06005N, which then had to be converted to grams, or 312.25grams. Our experimental values for T, H, and V When I equated our theoretical values and used them in the experiment the bar was stable once we removed the pins. We used T=342g, H=296g, and V=312g. In conclusion, my theoretical values for T, H, and V did match the experimental values I used. We got to see how you can balance a static equilibrium equation with knowledge of just a few things, like the mass of the bar and K. Then you can measure for the angles and after that you just solve for your unknowns....
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Static Equilibrium - grams, or 341.5grams. Then we solved...

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