# Le07 - ME 200 Thermodynamics I Lecture 7 Energy balance for...

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ME 200: Thermodynamics I Lecture 7: Energy balance for closed system Reading: Sections 2.5; SP7, 2.57, 2.64 Professor Hukam Mongia Office Hours: MWF 9:30 to 10:30 AM in ME 83 Other times email for appointment; Phone: 765-494-5640 Course Website: https://engineering.purdue.edu/ME200/ Course Secretaries: Diana Akers (ME 84) and Marilyn Morrison (ME 100) 9/8/2010 1 ME200 Therm I Lecture 07, Prof. Mongia

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9/8/2010 2 This lecture covers Energy balance for closed systems Closed system No mass transfer E 1 E 2 Heat in Q Work out, W Energy balance: E 2 +W = E 1 +Q E 2 -E 1 = Q-W D E = Q-W D KE + D PE + D U = Q-W ME200 Therm I Lecture 07, Prof. Mongia
9/8/2010 3 dE = d Q d W Because Q and W are not properties Go through worked-out examples 2.2 through 2.6 on your own. ME200 Therm I Lecture 07, Prof. Mongia

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Problem 2.53: Application of D E=Q-W, D E =E 2 -E 1 Process Q W E 1 E 2 E a -20 50 70 b 50 20 50 c -60 60 20 d -90 50 0 e 50 150 20 D E = 70 = E 2 -E 1 =50-E 1 ; E 1 = 50-70 = -20 D E=Q-W; Q = D E+W=70- 20 = 50 Process a? Process b? D E = E 2 -E 1 =50-20= 30 ; D W = Q- D E=50- 30 = 20 Process c?
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Le07 - ME 200 Thermodynamics I Lecture 7 Energy balance for...

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