rowreduceempty

Rowreduceempty - 0’s 6 Cover the top row in the matrix and start again with Step 1 on the matrix that remains Continue until entire matrix is in

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MATH 115 STEP BY STEP ROW REDUCTION 1. Write out the augmented matrix for the given system of equations. - 2 x 3 + 7 x 5 = 12 2 x 1 + 4 x 2 - 10 x 3 + 6 x 4 + 12 x 5 = 28 2 x 1 + 4 x 2 - 5 x 3 + 6 x 4 - 5 x 5 = - 1 2. Locate the leftmost column of the augmented matrix that is not all zeros. 3. Interchange the top row with another row (if necessary) to put a nonzero entry at the top of this column. 4. If the entry that is now at the top of this column is a 6 = 1, multiply the first row by 1 a to get a pivot. 5. Add suitable multiples of the top row to the entries below so that all entries below the pivot become
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Unformatted text preview: 0’s. 6. Cover the top row in the matrix and start again with Step 1 on the matrix that remains. Continue until entire matrix is in REF. -→ -→ -→ 7. Beginning with the last non-zero row and working up, add multiples of each row to the rows above to introduce 0’s above the leading 1’s. -→ -→...
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This note was uploaded on 01/13/2011 for the course MATH math 136 taught by Professor Brown during the Spring '08 term at Waterloo.

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