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HW25-Solution

# HW25-Solution - HW25 Solution Terry Cooke Cal Poly San Luis...

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HW25 - Solution Terry Cooke: Cal Poly San Luis Obispo

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Chapter 9, Solution 31 First note that 1 2 3 2 2 2 [(24)(6) (8)(48) (48)(6)] mm (144 384 288) mm 816 mm A A A A Now 1 2 3 ( ) ( ) ( ) x x x x I I I I where 3 2 2 1 4 4 1 ( ) (24 mm)(6 mm) (144 mm )(27 mm) 12 (432 104,976) mm 105,408 mm x I 3 4 2 3 2 2 3 4 4 1 ( ) (8 mm)(48 mm) 73,728 mm 12 1 ( ) (48 mm)(6 mm) (288 mm )(27 mm) 12 (864 209,952) mm 210,816 mm x x I I Then 4 (105,408 73,728 210,816) mm x I 4 389,952 mm 3 4 or 390 10 mm x I and 4 2 2 389,952 mm 816 mm x x I k A or 21.9 mm x k
Chapter 9, Solution 35 We have 1 2 ( ) 2( ) x x x I I I where 3 1 3 4 1 ( ) (40 mm)(40 mm) 12 213.33 10 mm x I 2 4 2 2 4 20 ( ) (20 mm) (20 mm) mm 8 2 3 x I 2 2 4 20 (20 mm) 20 mm 2 3 3 4 527.49 10 mm Then 3 4 [213.33 2(527.49)] 10 mm x I or 6 4 1.268 10 mm x I Also 1 2 ( ) 2( ) y

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