HW25-Solution

HW25-Solution - HW25 - Solution Terry Cooke: Cal Poly San...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: HW25 - Solution Terry Cooke: Cal Poly San Luis Obispo Chapter 9, Solution 31 First note that A A1 A2 A3 [(24)(6) (8)(48) (48)(6)] mm 2 (144 384 288) mm 2 816 mm 2 Now where Ix ( I x )1 ( I x )2 ( I x )3 ( I x )1 1 (24 mm)(6 mm)3 (144 mm 2 )(27 mm) 2 12 (432 104,976) mm 4 105, 408 mm 4 ( I x )2 ( I x )3 1 (8 mm)(48 mm)3 73, 728 mm 4 12 1 (48 mm)(6 mm)3 (288 mm 2 )(27 mm) 2 12 (864 209,952) mm 4 210,816 mm 4 (105, 408 73, 728 210,816) mm 4 Then Ix 389,952 mm 4 or Ix 390 103 mm 4 kx 21.9 mm and 2 kx Ix A 389,952 mm 4 816 mm 2 or Chapter 9, Solution 35 We have where Ix ( I x )1 2( I x ) 2 ( I x )1 1 (40 mm)(40 mm)3 12 213.33 103 mm 4 ( I x )2 8 (20 mm) 4 2 (20 mm) 2 4 20 mm 3 2 2 2 (20 mm) 2 4 20 3 20 mm 527.49 103 mm 4 Then Ix [213.33 2(527.49)] 103 mm 4 or Also where Iy ( I y )1 ( I y )2 Ix 1.268 106 mm 4 ( I y )1 2( I y ) 2 213.33 103 mm 4 1 (40 mm)(40 mm)3 12 8 (20 mm)4 62.83 103 mm 4 Then Iy [213.33 2(62.83)] 103 mm 4 or Iy 339 103 mm 4 Chapter 9, Solution 37 We have and Subtracting or I AA I AA I BB I BB 2 d2 I I Ad12 2 Ad 2 2 d2 (1) A d12 d12 I AA A I BB (25 mm)2 3600 mm 2 (12 23.9)106 mm 4 4000 mm 2 or d 2 (4000 mm 2 )(25 mm) 2 or I 60.0 mm Using Eq. (1): I 12 106 mm 4 9.50 106 mm 4 ...
View Full Document

This note was uploaded on 01/13/2011 for the course ME 211 taught by Professor Staff during the Fall '05 term at Cal Poly.

Ask a homework question - tutors are online