October 24 Solutions - 8.49. IDENTIFY: The location of the...

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8.49. IDENTIFY: The location of the center of mass is given by Eq. 8.48. The mass can be expressed in terms of the diameter. Each object can be replaced by a point mass at its center. SET UP: Use coordinates with the origin at the center of Pluto and the + x direction toward Charon, so P 0 x C 19,700 km x . 33 41 36 m V r d . EXECUTE: 3 3 1 C P P C C C C 6 cm C C C 3 3 3 3 11 P C P C P C P C 66 d m x m x m d x x x x m m m m d d d d . 3 3 cm [1250 km] (19,700 km) 2.52 10 km [2370 km] [1250 km] x . The center of mass of the system is 3 from the center of Pluto. EVALUATE: The center of mass is closer to Pluto because Pluto has more mass than Charon. 8.54. (a) IDENTIFY and SET UP: Apply Eq. 8.28 and solve for 1 m and 2 . m EXECUTE: 1 1 2 2 cm 12 m y m y y mm 1 1 2 2 1 cm (0) (0.50 kg)(6.0 m) 1.25 kg 2.4 m m y m y m y and 1 0.75 kg. m EVALUATE: cm y is closer to 1 m since . (b) IDENTIFY and SET UP: Apply / d dt av  5 for the cm motion. EXECUTE: 3 cm cm ˆ 1.5 m/s . d t dt v ai 55 (c) IDENTIFY and SET UP: Apply Eq. 8.34.
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This note was uploaded on 04/03/2008 for the course PHYSICS 140 taught by Professor Evrard during the Fall '07 term at University of Michigan.

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October 24 Solutions - 8.49. IDENTIFY: The location of the...

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