Homework 4 Lecture 15

9390708015880440590690494568872

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Unformatted text preview: ons for the general matrix were supplied in the lecture notes. The matrix was divided by the values of mass 1 = 1 and mass 2 = 2. >> B = [2/1 ‐1/1; ‐1/2 2/2] B = 2.000000000000000 ‐1.000000000000000 ‐0.500000000000000 1.000000000000000 >> [v e] = eig(B) v = 0.939070801588044 0.590690494568872 ‐0.343723769333440 0.806898221355074 e = 2.366025403784438 0 0 The first column of v shows that the two masses are moving opposite of each other (reverse of what the case is with equal masses) and with the highest mode. In the case of equal masses, the lowest mode corresponded to the first column, but here that is switched. The s...
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