# T1a10s - Assignment 10 solutions(Fall term Physics 102...

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10.12 (a) As the temperature drops by 20°C, the length of the pendulum changes by () i LLT α ∆= Thus, the final length of the rod is ()( ) ( ) 1 64 19 10 C 1.3 m 20 C 4.9 10 m 0.49 mm −− ⎡⎤ ° °= −× = ⎣⎦ 1.3 m 0.49 mm f L = Assignment 10 solutions (Fall term Physics 102) (b) From the expression for the period, 2 TL π = g , we see that as the length decreases the period decreases. Thus, the pendulum will swing too rapidly and the clock will run fast . 10.15 From ( fi i LL L L T ) , the final value of the linear dimension is − = ( ) i LL LT =+ . To remove the ring from the rod, the diameter of the ring must be at least as large as the diameter of the rod. Thus, we require that ( ) ( ) ff brass al LL = , or ( ) ( ) brass brass brass T L L T + ∆= + This gives T αα . (a) If 10 L = , .01 cm ()( ) ()( ) 11 -6 -6 10.01 10.00 199 C 19 10 C 10.00 24 10 C 10.01 T = − ° ×° , so 20.0 C 199 C= TT T °− ° 179 C which is attainable ° . (b) If 10 L = , .02 cm -6 -6 10.02 10.00 396 C 19 10 C 10.00 24 10 C 10.02 T = , and = 376 C which is below absolute zero and unattainable −° 347

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CHAPTER 11 10.55
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T1a10s - Assignment 10 solutions(Fall term Physics 102...

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