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Characteristics of Steady State Response and Example ppt

# Characteristics of Steady State Response and Example ppt -...

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Characteristics of Steady State Response for Low and High Excitation Frequencies

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Problem 17 Page 215
Steady State Response m 1 = c 1 4 = k 2 = F0 2 = γ c 2 2 m = γ 0.031 = ϖ n k m = ϖ n 1.414 = ∆ ϖ ( 29 m ϖ n 2 1 ϖ 2 ϖ n 2 - 2 γ ϖ 2 ϖ n 2 + = Maximum occurs at ϖ m ϖ n 1 γ 2 - = ϖ m 1.403 = Steady State Amplitude (SSA) as a function of Driving Frequency Amp
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Unformatted text preview: ϖ ( 29 F0 ∆ ϖ ( 29 = Maximum Steady State Amplitude Amax Amp ϖ m ( 29 = Amax 5.679 = Plot of SSA vs ϖ ϖ 0.0 0.1 , 5 .. = 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 0.6 1.2 1.8 2.4 3 3.6 4.2 4.8 5.4 6 Amp ϖ ( 29 ϖ Problem 17 Page 215 Continued …. Units not shown...
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