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Lecture 23 - EE‘E‘ 8‘320 WWfizzB p.7 Two—8...

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Unformatted text preview: EE‘E‘ 8‘320 WWfizzB/ p.7; Two—8% GE‘Amg LMg—mra/Z—ZW‘, 25, -— #ofiflrcv .5, =ra- ”Lo/M, {6,4, =7¢11=71~L = 0—9 m/V .22a -.0./ML sf“, ==> Cm = 4 ~» 4.9 MW 5 ofirm-m1M/7f4/u m/ 24mg; ~ ( 312 M He—j I: E Z/MM .. [at , I a/Mm m1 mg ”I ”3‘ 1 fl\ LL} 33.! i": C;- LG “'1 E7. 4/50] 4.32,: 66““ = M = /3.3 cpl: C 0.3fF ca/Wm’ 4%.er (“Zn/“7H4 Zea/v ‘I‘wmreawo, Lazi- I/waé , 1491,“; (Pf/J' %A boom; {{t PM +79 5T“. 712 DC Amsf W ’3 4m, {99%, (M11 flLI?_ Q 2 : 0530930) “((0) 1L ~— gown/02‘ $76,092 / \ (537%6/ 1.00 1.05 1.10 1.1550 1.20 1.25 1.00 1.05 1.10 1.1577 1.20 1.25 ITI 1.193 1.124 1.062 1.000 0.953 0.905 ITI 1.196 1.128 1.066 1.000 0.957 0.908 (Ewan 132 $01270) 2.034 2.054 2.074 2.095 2.111 2.129 2.109 2.133 2.156 2.182 2.201 2.223 arg(T) 180-arg(T) Neglecting zero -116.565567 —117.700014 ~118.811361 -120.007029 -120.964375 -122.006028 arg(T) -120.854311 —122.202335 —123.527132 -125.026931 -126.106649 -127.361341 #2; 63.4 62.3 61.2 60.0 xxx 59.0 58.0 180-arg(T) Including zero 59.1 57.8 56.5 55.0 53.9 52.6 P. 2/2'3 EEE 5320,." f” , Exercise: Quiz 3 from 2001 Lecture {25 vcc=+1ov V I 343 Unity-gain output stage; Rin 5°? Rout Q7 —.~- 0 Assume: EN = 150, VAN = 150 V, [5p 2 50, VAP = 50 V; transistors match. VCESat E 0.2 V, VBBon E 0.1 V ' 1. Pick R3 and R4 so that 1C7 = 250 “A and [C] = 1C2 = 20 uA. 2. Estimate the common-mode input voltage range. 1 . - 1 3. Calculate the differential-mode input resistance. UV" 0 t6) 4. Approximately what value should CC be to get a 45° phase margin for unity closed-loop gain, assuming the compensated open-loop circuit has only a single non-dominant pole, at 5 MHz. 5. What slew rate will the CC from (4.) give? 6. Suppose the op amp, compensated as in (4.), is used in the circuit below. a. Estimate the resulting closed—loop dominant pole frequency. b. Will the resulting phase margin be better or worse than 45°? sax 5K Bonus: (5%) Estimate the DC voltage gain 05 ch can am? . 4‘56“???” H . (200' mm?“ 3/01?»va 1‘23 voc=+tov 4/5 V0 Unity-gain . outputstage; I Ring .4 V VEB—é-IOV , m“ («av—a7 ® *3 .1 n”, ~352— ' ' 25’0 - . 2 ,— fl¢3(wIcUM J’swr‘ca) &’ L2...“ l./ “A- 5. 70/44- @(c*.« .644?) VCMMéx .—_ Va ”Weeks-ml” 64/92“ - (2.051139. "VBEA: ' 1‘19, 0.10 ’— .03- - .08 —o.‘70 '3' 4,0,, erw ‘ Vce‘s + Veé‘S‘ + “Rent" " ‘VBEII + V65 0.? + 0.“! t— on. - ~. 077 ” 1° “1 ”3-11" (A; ’ ”“52“" - 14/} Céédc ,gfli_ C W 6”,? ”fl,“ — 019 /v et. 01'96‘3 K ; grow/1.. wt 2w“ , 70-7 65w CC 2W 5736, 2 ~. 43”” .gm. _.. .. 224 41 50 SHEETS 22-142 100 SHEETS 22 144 200 SHEETS fie = Ir/A/a 4- 13‘/ (223/014) % A6340. Ve = he "‘ 55972314 “7““ _ . (8,; Away/'1 = 46/74/105”; AIM/L afl/e, amaze 47512 $7446 7‘ /°‘“4/V > «(.7 = 60m %& - mo . 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Vcc Figure 5.25 Quasi-complementary Class B. output stage.‘ , Fig. 2-9. Complete schematic .of LMIOI (LMIOIA, ctc.). . uv‘m‘ 22-141 50 SHEETS 22.142 100 SHEEFS 22-144 200 SHEETS ‘rL-‘tfi ‘. “I'M/pr W I quq . I I HI [3/73 6N“; 4— "’ ’ MA‘ éanfirma mweaxfi flow (Xv/.944 flew/é 4- “#7 JW (”IQ/wt) cow-M 7 we; I}. - ' fa a. ganja/C MPM law-W 1243‘: Thu 1312:? : .«wUUW: 25— we (2'6 .132 :35. («47an m), EEE 5320 BipolarvAnalog IC Design ' Lecthre # 2:3 5 “MMI/ . / Compensation Thought Questions 1. It is often stated that for O < [3 < l (where [i is the feedback factor B = T/ADM), B = l is the worst case for stability. .- Why? - What situations can make stability worse than B = 1? - Could there be situations with l [3 l < 1 where stability is worse than B: 1? 2. Show ways you could build an‘ op amp circuit where stability can be varied without affecting A“ ‘ and'without changing the compensation capacitor. 3. In most op amp amplifiers] there is a simple trade-off between the closed—loop bandwidth and the closed—loop gain. — What is that trade—off? _ - Why does that trade—off not apply to current-feedback op amps? 4. The feedforward zero in a Miller-compensated Op amp is in the right half of the s—plane, so it hurts stability. (The zero keeps the gain from dropping as fast, while it is adding to the phase delay). - Show how adding a resistor R2 in series with the compensation capacitor can move the feedfor— ward zero to improve the phase margin. ' — What value of R2 would move the zero to infinite frequency? ~ What value would move the zero into the left half of the s-plane to cancel the non—dominant pole? — If increasing the value of R2 improves the phase margin, wouldn’t it be a good thing to increase R2 to very high values? Why or why not? EEE 5320 Bipolar Analog IC Design Lecture '24 MN Compensation Thought Questions . P’/‘*"- 1. It IS often stated that for 0 < B < 1 (where Bis the feedback factor B: T/ADM), B: 1 IS the worst case for stability. — Why? - What situations can make stability worse than B = 1? - Could there be situations with l B l < ‘1 where stability is worse than B :1? 0< 18K 1 $7 I916 is Féfl/{A(K06 emf/ex), 7%“ {34 7: wont—W, [92W If 341/94 % étjé/efli‘ T, 447?, $460. . PM” flw (”W Mai/6“”) 7%” sag/,6, wax/Le Lomsa 7%“ Kn 1/0/14? J(°/(9~J.e/V 6450-4 Mg“; WMZ fO/C’J 7409/ 0(2414017“ f/M avak EEE 5320- Bipolar Analog IC Design ; Lecture 24 2. Show ways you could build an op amp circuit where stability can be varied without affecting Am ‘ ' and without changing the compensation capacitor. - ('31. fix Smquhmjug RA— w {35 W (447»; Van/«a4 fii {EB Look/44? W T, wit—L flatpédgl x439. fight WMa'rg, T Maia—@768“),- %% rmPNt/‘e 5&6.ij w rt tie/[4:44, c/oxeo/F/afif Iowan/[é ‘W/ s/m HAM WW . 3. In most op amp amplifiers I there is a simple trade-off between the closed—loop bandwidth and the closed-loop gain. - What is that trade-off? - Why does that trade—off not apply to current—feedback op amps? 2(f‘zL It 272‘ ’ a k'%—“ 6:: / 50 ,McW—ng Ayn 5: 400 rs WWW wanna/7 pafwfiM-fl +9 wt Q’CBCJ. k lsl-e‘édrrw/Q (\D 4 I99), EEE 5320 Bipolar AnalogIC Design ‘ . .1 A ' '_ , Lecture :4 P- 3/3 4. The feedforward zero in a Miller-compensated op amp is in the right half of the s-plane, so it hurts stability. (The zero keeps the gain from dropping as fast, while it is adding to the phase delay.) - Show how adding a resistor R2 1n series with the compensation capacitor can move the feedfor- ward zero to improve the'phase margin. ~ What value Of Rz would move the zero to infinite frequency? - What value would move the zero into the left half of the s- plane to-cancel the non- -dominant pole? - If 1ncreasing the value of R21mproves the phase margin, wouldn’t 1t be a good thing to increase Rz to very high values? Why or why not? %' a sled/7 WW Mm 52 +91%, egg 1% -f/W Zf7fSCLQWH/L1/‘lfi {WMMJ’MMWJC 9%; film (444/ A”) 4M 7% if: Mu—gémawqe loo/e. I; 1%in W0 “WM 1am A1494 ATM/K7 2752 PZWW w “ff/47 , bffiéflm i. we 79, «mm 1;“ WW w /( MA? 112 WW . 19% mm fame/7 fiwwm/J / rel/m1 (we/ca Add at Manda”! WW :4) (( abrfl “Tm/J 71/47 s/me 776: Lflefmvafl ,: «Lb/7‘?“ Page 143/, flag/of. ...
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