This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: and so the average kinetic energy is once again . We may now use the Virial Theorem (as in c) to determine the average potential energy of this system, for which n = 6, 3a. From eq. 1.31, The average speed is where we define and . The general solution to an integral of this form is For m = 3, Remembering that , the solution to the integral is The last step was performed recalling and . b. The most probable velocity is reached at the maximum of the probability distribution. Taking the derivative of P(v) with respect to velocity and setting the value equal to zero will give the maximum velocity. Recalling the values of the constants c 1 and c 2 , after factoring out c 1 e c 2 v 2 2 v the above result implies that 1 c 2 v 2 = when v = v max and so c. The required velocities are obtained using the molecular weights of N 2 (28 g/mol) and H 2 (2 g/mol), as well as using the fact that in the SI unit system 1 J = 1 kg (m/s) 2 ....
View
Full
Document
 Fall '10
 BenAmotz
 Physical chemistry, pH, Energy, Kinetic Energy, Mass, Potential Energy, average kinetic energy

Click to edit the document details