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Unformatted text preview: Chapter 5 Solutions 5.1 The PrimDijkstra Algorithm Arbitrarily select node e as the initiaJ frag ment. Arcs are added in the following order: (d,e), (b,d), (b,c) {tie with (a,b) is broken arbitrarily}, (a, b), (a, J). Kruskal's Algorithm Start with each node as a fragment. Arcs are added in the following order: (a,f), (b,d), (a,b) {tie with (b,c) is broken arbitrarily}, (b,c), (d,e). The weight of the MST in both cases is 15. 5.2 The BellmanFord Algorithm By convention, D~h) = 0, for aJI h. Initially DP) = d li , for all i :# 1. For each successive h ?: 1 we compute D~h+l) = minj[Djh) + d ji ), for all i :f 1. The results are summarized in the following table. D~ D 2 D3 D~ D~ Shortest path arcst • • t t t 1 2 4 4 4 4 4 (1,2) 3 5 5 5 5 5 (1,3) 4 00 7 7 7 7 (2,4) 5 00 14 13 12 12 (6,5) 6 00 14 10 10 10 (4,6) 7 00 00 16 12 12 (6,7) tThe arcs on the shortest path tree are computed after running the Bellman Ford aJgorithm. For each i:f 1 we include in the shortest path tree one arc U,i) that minimizes Bellman's equation. Dijkstra's Algorithm Refer to the algorithm description in the text. Ini tially: D 1 = 0; D; = d u for i :f 1; P = {l}. The state after each iteration is Next assume A=l and Cl=O. On the arrival of an idle slot in the downstream direction, 1) Place the frame in the idle slot, setting the busy bit; 2) If there is a waiting frame in the supplementary queue, put it in the vinu::ti queue, place C2 in counter 1 and set C2 to 0; 3) If there is no waiting frame, set A=O. On the arrival of a request bit in the upstream direction, increment C2. Next assume A=O. On the arrival of an idle slot in the downstream direction, decrement C2. On the arrival of a request bit in the upstream direction, increment C2. On the arrival of a frame to be transmitted, put it in the vinual queue, place C2 in counter 1 and set C2 to O. shown in the table below. P is not shown but can be inferred from i. Only the Dj's which are updated at each step are shown. Iteration i Dl D 2 D 3 D 4 Ds D s D 7 Arc added initial 4 5 00 00 00 00 1 2 5 7 14 00 00 (1,2) 2 3 7 14 14 00 (1,3) 3 4 13 10 00 (2,4) 4 6 12 12 (4,6) 5 5 12 (6,5) 6 7 (6,7) 5.3 Let Pij be the probability that link (i, j) fails during the lifetime of a virtual circuit. Let PA: be the probability that a path k = (A, i, ... ,j, B) remains intact. Since links fail independently we have: We want to find the path k for which PA: is maximized. Equivalently, we can find the path k for whichIn PA: is minimized. Since the arc weights Pij are small, 1  Pij is close to 1 and we may use the approximation In z ::::: z 1. This gives:In PA: ::::: PAi + ... + PjB Therefore, the most reliable path from A to B is the shortest path using the weights given in the figure. Applying Dijkstra's algorithm gives the shortest path tree. We proceed as in problem 5.2....
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This note was uploaded on 01/17/2011 for the course ECE 442 taught by Professor Biswas during the Fall '09 term at Michigan State University.
 Fall '09
 Biswas

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