ECE3040_Homework8_Solutions

ECE3040_Homework8_Solutions - (30 points) ECE 3040B:...

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ECE 3040B: Homework #8, Solution April 3, 2009 Page 1 of 5 G EORGIA I NSTITUTE OF T ECHNOLOGY S CHOOL OF E LECTRICAL AND C OMPUTER E NGINEERING ECE 3040B: Microelectronic Circuits Spring Semester 2009, Homework #8 SOLUTIONS Note : Jaeger, Blalock use different abbreviations than Pierret Pierret: I D = Z μ n C o L (V g V T )V D V D 2 2 ; Jaeger, Blalock: I D = K n ' W L (V GS V TN )V DS V DS 2 2 with K n ' = μ n C o ,W = Z,V GS = V g ,V TN = V T ,V DS = V D 1. Pierret, Problem 16.4 (a)–(d) (20 points) (a) φ F = kT q ln N D n i = 11.5 kT q = 0.30 V (b) W T = 2K s ε 0 qN D ( 2 φ F ) = 4K s ε 0 kT q 2 N D ln N D n i = 0.89 μ m (c) ε S = qN D K s ε 0 W T = 2qN D K s ε 0 ( 2 φ F ) = 13.6 kV / cm (d) V g = φ s + K s K o x 0 ε S = 2 φ F K s K o x 0 2qN D K s ε 0 ( 2 φ F ) = 1.01V
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ECE 3040B: Homework #8, Solution April 3, 2009 Page 2 of 5 2. Pierret, Problem 16.7 (a)–(i)
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Unformatted text preview: (30 points) ECE 3040B: Homework #8, Solution April 3, 2009 Page 3 of 5 3. MOSFET: I-V Characteristic (20 points) The output characteristic for an NMOS transistor (I D vs V DS for different V GS ) is given in the graph on the right. What are the values for K n W/L and V TN for this transistor? ECE 3040B: Homework #8, Solution April 3, 2009 Page 4 of 5 4. MOSFET: Q-Point Analysis (30 points) Find the Q-point for the transistor (a PMOS transistor) on the right. Assume that V TP = 1 V, W/L = 1/1 and K p = 25 A/V 2 . ECE 3040B: Homework #8, Solution April 3, 2009 Page 5 of 5...
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ECE3040_Homework8_Solutions - (30 points) ECE 3040B:...

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