ch15_solutions - 15-485 CHAPTER 15 15.1ac equivalent...

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Unformatted text preview: 15-485 CHAPTER 15 15.1ac equivalent circuit 17.2 kΩ3.3 kΩ250 ΩRB2Q2Q3620ΩRD1M1RG10 kΩ1 MΩRINROUT4.7 kΩ51.8 kΩRC2RB3RE3RL4.7 kΩRE2RS1200 ΩviRIRin2Rin3The Q-points and small-signal parameter values have already been found in the text. The bypass capacitors do not affect Rin: Rin=RG=1 MΩ| Av=Rin10kΩ+RinAvt1Avt2Avt3RL1=620Ω17.2kΩ(29rp2+bo2+1(291.6kΩ(29=598Ω2.39kΩ+151(291.6kΩ(29=597ΩAvt1= -gm1RL11+gm1RS1= -0.01 597(291+0.01(29200= -1.99 | RL2=3.54kΩ(Eq. 15.7)Avt2= -bo2RL2rp2+bo2+1(291.6kΩ=-150 3.54kΩ(292.39kΩ+151(291.6kΩ=-2.18Avt3= +0.950 | Av= -1MΩ10kΩ+1MΩ1.99(29-2.18(290.950(29= +4.08Rout=3300Ω(29Rth3+rp3bo3+1| Rth3=RI3Ro2=RI3ro21+bo2RE2Rth2+rp2+RE22245RI3=4.31kΩRout=3.30kΩ(294.31+1.0081kΩ= 64.3Ω15.2vovi=vov3v3v2v2v1v1vi| vov3=bo3+1(29RL3rp3+bo3+1(29RL3=81( 292321500+81( 29232=0.926v3v2= -bo24700Rin3(29rp2+bo2+1(29RE2| Rin3=rp3+bo3+1(29RL3=1500+81( 29232=20.3kΩv3v2= -150 4.70kΩ20.3kΩ(292.50kΩ+151(291.40kΩ= -2.68 | v2v1= -gm1Ri1Rin2(291+gm1RS115-486 ac equivalent circuit 10.0 kΩ4.70 kΩ620ΩRI1232 ΩRI2Q2M1Q3RIN2v2RIN3RL3v3vo+-viRI1 MΩ1.6 kΩ1.4 kΩThe Q-points and small-signal parameter values have already been found in the text. Rin2=rp2+bo2+1(29RE2| Rin2=2.50kΩ+151(291.40kΩ= 214kΩv2v1= -0.01 620Ω244kΩ(291+0.01 1.6kΩ(29= -0.364v1vi=RG10kΩ+RG=0.990 | Av=vovi=0.926(29-2.68(29-0.364(291( 290.990(29= +0.89415.3M1: ID=0.012VGS+2(292| VGS= -9000ID→VGS= -1.80VID=0.012-1.8+2(292=200 mA| VDS=15-15kΩ+9kΩ(29ID=10.2 Vgm=2 10mA/V2(290.2mA(29=2mS| ro=50+10.2(29V0.2mA=301kΩQ2: VEQ2=1543kΩ43kΩ+160kΩ=3.18V| REQ2=160kΩ43kΩ=33.9kΩIC2=1503.18 - 0.733.9kΩ+151 1.6kΩ(29=1.35 mA| VCE2=15-4.7kΩ+1511501.6kΩIC=6.49 Vgm2=40 1.35mA(29=54.0mS| rp2=15054.0mS=2.78kΩ| ro2=80+6.49(29V1.35mA=64.1kΩQ3: VEQ3=15120kΩ120kΩ+91kΩ=8.53V| REQ3=120kΩ91kΩ=51.8kΩIC3=808.53- 0.751.8kΩ+81 2.2kΩ(29= 2.72 mA| VCE3=15-81802.2kΩIC=8.93 Vgm3=40 2.72mA(29=109mS| ro3=60+8.93(29V2.72mA=25.3kΩ| rp3=80109mS=734Ω15-487 Av=RG10kΩ+RGAvt1Avt2Avt3Avt1= -2mS(29301kΩ15kΩ33.9kΩ2.78kΩ(29= -4.36Avt2= -54.0mS(2964.1kΩ4.7kΩ51.8kΩ734+81 2.2kΩ250Ω(29(29= -180Avt3=81 2.2kΩ250Ω(29734+81 2.2kΩ250Ω(29=0.961 | Av= -4.36-180(290.961(291MΩ10kΩ+1MΩ =747vbe3=vb31-Avt3(29=0.99Avt1Avt2vs1-Avt3(29≤5mV| vs≤0.0050.99 4.36(29180(291-0.961(29=165mVThe gain is actually reduced rather than improved. The signal range increased since the gain was reduced....
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This note was uploaded on 01/17/2011 for the course ECE 3040 taught by Professor Hamblen during the Fall '07 term at Georgia Institute of Technology.

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ch15_solutions - 15-485 CHAPTER 15 15.1ac equivalent...

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