18705
CHAPTER 18
18.1
a
( 29
T
=
A
b
= ∞

A
v
=
1
b
=
5

FGE
=
0
b
( 29
A =10
86
20
=
20000

T
=
20000 0.2
(
29
=
4000
A
v
=
A
1
+
A
b
=
20000
1
+
4000
=
5.00

FGE
=
100%
1
+
A
b
=
100%
4001
=
0.025%
c
( 29
T
=
10 0.2
(
29
=
2

A
v
=
A
1
+
A
b
=
10
1
+
2
=
3.33

FGE
=
100%
1
+
2
=
33.3%
18.2
a
( 29
b
=
R
1
R
1
+
R
2
=
1
k
Ω
101
k
Ω
=
1
101
b
( 29
T
=
A
b
=
10
80
20
1
101
=
99.0

A
v
=
A
1
+
A
b
=
10
4
100
=
100
18.3
a
( 29
b
s
( 29
=
R
1
R
1
+
R
2
=
1
k
Ω
101
k
Ω
=
1
101

T s
( 29
=
A
b
=
10
80
20
1
101
=
99.0
A
v
= 
R
2
R
1
A
b
1
+
A
b
= 
100
k
Ω
1
k
Ω
99
100
= 
99
18.4
b
s
( 29
=
Z
1
s
( 29
Z
1
s
( 29
+
Z
2
s
( 29
=
R
R
+
1
sC
=
s
s
+
1
RC
=
s
s
+
10
4

A
=
10
80
20
=
10
4
T s
( 29
=
A
b
=
10
4
s
s
+
10
4

A
v
= 
Z
2
Z
1
A
b
1
+
A
b
= 
1
sRC
10
4
s
s
+
10
4
1
+
10
4
s
s
+
10
4
= 
1
RC
1
s
+
1
Instead of a pole at the origin,
the integrator has a low
 pass response
with a pole a
w
=1 rad/s.
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