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ch18_solutions

# ch18_solutions - CHAPTER 18 18.1(a T = A = 86 | Av = 1 =5 |...

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18-705 CHAPTER 18 18.1 a ( 29 T = A b = ∞ | A v = 1 b = 5 | FGE = 0 b ( 29 A =10 86 20 = 20000 | T = 20000 0.2 ( 29 = 4000 A v = A 1 + A b = 20000 1 + 4000 = 5.00 | FGE = 100% 1 + A b = 100% 4001 = 0.025% c ( 29 T = 10 0.2 ( 29 = 2 | A v = A 1 + A b = 10 1 + 2 = 3.33 | FGE = 100% 1 + 2 = 33.3% 18.2 a ( 29 b = R 1 R 1 + R 2 = 1 k 101 k = 1 101 b ( 29 T = A b = 10 80 20 1 101 = 99.0 | A v = A 1 + A b = 10 4 100 = 100 18.3 a ( 29 b s ( 29 = R 1 R 1 + R 2 = 1 k 101 k = 1 101 | T s ( 29 = A b = 10 80 20 1 101  = 99.0 A v = - R 2 R 1 A b 1 + A b = - 100 k 1 k 99 100  = - 99 18.4 b s ( 29 = Z 1 s ( 29 Z 1 s ( 29 + Z 2 s ( 29 = R R + 1 sC = s s + 1 RC = s s + 10 4 | A = 10 80 20 = 10 4 T s ( 29 = A b = 10 4 s s + 10 4 | A v = - Z 2 Z 1 A b 1 + A b = - 1 sRC 10 4 s s + 10 4 1 + 10 4 s s + 10 4 = - 1 RC 1 s + 1 Instead of a pole at the origin, the integrator has a low - pass response with a pole a w =1 rad/s.

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