formulae2

Formulae2 - (Only In Equilibrium 2nd Law v F total = mva 3rd Law v F A on B =-v F B on A Friction(n = Normal Force f s ≤ f s,max = μ s n f k =

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1 Mathematics Quadratic Equation, ax 2 + bx + c = 0 : x = - b ± b 2 - 4 ac 2 a Trigonometry: a 2 + b 2 = c 2 a a a a a a a θ b c a sin θ = a/c cos θ = b/c tan θ = a/b tan θ = sin θ cos θ Fundamental Constants g = 9.80 m/s 2 c = speed of light in vacuum = 3 . 00 × 10 8 m/s m e = mass of electron = 9 . 11 × 10 - 31 kg m n = mass of neutron or proton = 1 . 67 × 10 - 27 kg G = gravit. constant = 6 . 673 × 10 - 11 N · m 2 /kg 2 R E = radius of Earth = 6 . 37 × 10 6 m M E = mass of Earth = 5 . 98 × 10 24 kg M L = mass of Moon = 7 . 35 × 10 22 kg M S = mass of Sun = 1 . 99 × 10 30 kg Kinematics vV av = v r 2 - v r 1 t 2 - t 2 = Δ v r Δ t va av = vV 2 - vV 1 t 2 - t 2 = Δ vV Δ t vV = lim Δ t 0 Δ v r Δ t va = lim Δ t 0 Δ vV Δ t Uniform linear acceleration a = const: x = x 0 + V 0 x t + 1 2 a x t 2 V x = V 0 x + a x t V 2 x = V 2 0 x + 2 a x ( x - x 0 ) Radial Acceleration: a rad = V 2 R Projectile Motion: Range R = V 2 0 sin 2 θ 0 g Max . Height h = V 2 0 sin 2 θ 0 2 g Mechanics Newton’s Laws: 1st Law: X v F = 0 ,
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Unformatted text preview: (Only In Equilibrium) 2nd Law: v F total = mva 3rd Law: v F A on B =-v F B on A Friction (n = Normal Force): f s ≤ f s,max = μ s n f k = μ k n, μ k < μ s Gravity: F g = G m 1 m 2 r 2 w = mg Elastic Forces: F el =-kx Work & Energy Kinetic Energy: K = 1 2 mV 2 Work: W = F s cos φ Work / Kinetic Energy Theorem: W total = K f-K i = Δ K Gravitational Potential Energy: U grav = mgy Elastic Potential Energy: U el = 1 2 kx 2 Conservation of Energy: E f = E i K f + U f = K i + U i...
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This note was uploaded on 01/17/2011 for the course PHYS 6a taught by Professor Stanek during the Fall '07 term at UCSB.

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