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Oct_19 - 2 ion/cell= 4 no of S-2 ion/cell = 4 ½ √3a =...

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a = 2r Cl + 2r Na
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Calcium Fluoride CaF 2 (fluorite) Ca 2+ ions form an FCC unit cell with F - ions filling all the T d holes in the cube CN (Ca 2+ ) = 8 CN (F - ) = 4 no of Ca 2+ ion/cell= 4 no of F - ion/cell = 8 ½ · √3a = 2r Ca + 2r F stoichiometry of Ca 2+ to F - = 1:2
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Zinc Sulphide ZnS (zincblende) S -2 ions form an FCC unit cell with Zn 2+ ions filling half the T d holes in the cube CN (S -2 ) = 4 CN (Zn 2+ ) = 4 no of Zn
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Unformatted text preview: 2+ ion/cell= 4 no of S-2 ion/cell = 4 ½ · √3a = 2r Zn + 2r S stoichiometry Zn 2+ to S-2 = 1:1 Example Problem Given the density of CaF 2 is 3.180 g/cm 3 , how far apart are the Ca 2+ and F-centres ? MW 4 CaF 2 = 312.28 vol = 1.63 x 10-22 cm 3 a = 5.46 x 10-8 cm ½ · 3a = 2r √ Ca + 2r F r Ca + r F = 2.364 x 10-8 cm = 2.364 Å...
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Oct_19 - 2 ion/cell= 4 no of S-2 ion/cell = 4 ½ √3a =...

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