2-35 sol - = \"r' Fj + F2"os(o) + r 1 cos(e + p)...

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Problem 2-35 Three forces act on the bracket. Determine the magnitude and direction dof F, so that the resultant force is directed along the positive _r'axis and has a magnitude of Fo. Units Used: tN:to3N Given: Fn=lkN Fz=450N F;=ZOON a=45deg f=30deg Solution: + Fn :SF; r'acos(B) = .t Fer- SF;
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Unformatted text preview: = \"r' Fj + F2"os(o) + r 1 cos(e + p) F2sin(a) - rlsrn(e+ p) ,r'7 cos( 0 + fl : Fpcos(/)) - Fj * n2 cos(a) Fl sin(o + p) = 12sin(a) + rpsin(p) ( F2 sin(a) + rasin(p) ) A = a l & n i - i _ n \rpcos(/,l _ Fj_r2cos(a)) r 0 = 3 7 d e g Fr = ,,|(rpcos(p) - Fj - 12"os(a))'+ (r'.2stn(a) + rprin(p))2 FY = '889 N...
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This note was uploaded on 01/20/2011 for the course PHYS 170 PHYS 170 taught by Professor Macmillan during the Spring '10 term at The University of British Columbia.

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