Homework 5 Solutions

Homework 5 Solutions - 14.7 Newton Method The first and...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 14.7 Newton Method The first and second derivatives can be expressed as: = 3.5 + 2 - 4 3 - 2 , = 2 - 2 - 2 , = 2 -2 , -2 -2 2 2 2 From this the Hessian Matrix is expressed as: = and it follows that 2 = -2 . 2 2 =2, = -2 , . 25 -.25 -1 = . -.25 -.25 3.5 Lastly, the gradient evaluated at our initial x = (0,0) is ( ) = . 2 . 25 -.25 3.5 -.375 Using Newton's method, +1 = - = . -.25 -.25 2 1.375 ...
View Full Document

This note was uploaded on 01/20/2011 for the course ENG EAD 115 taught by Professor Rocke during the Spring '10 term at UC Davis.

Ask a homework question - tutors are online