E7_Lab02_Solutions_Fall_2010

# E7_Lab02_Solutions_Fall_2010 - E7 Lab 02 Solutions 1. A...

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E7 Lab 02 Solutions 1. A vector: [0 3 6 9] B vector: [4 10 16] 2. C = 3:2:11. Note the third value may be any number between 11 and 12.99. 3. D vector: Empty matrix: 1-by-0 E vector: Empty matrix: 1-by-0 4. F = 5:-.25:4.25. Note third value may be any number between 4.01 and 4.25. 5. The colon operator creates a row vector. There are typically three input arguments, the first argument is the beginning value of the vector, the second value is the step and the third value is the last value of the vector. Omission of the second value leads to a step of 1. If no value exists between the first and last value using the step size, an empty vector is created. 6. linspace(0,1,10) gives [0 1.1111, …, 8.8889, 10] Step size is 1.1111. linspace(0,1,11) gives [0 1, …, 9, 10] Step size is 1.0000. 7. A = linspace(5,8,13); 8. linspace(10,1,10) gives [10, 9, …, 2, 1]. 9. logspace(0,1,10) gives [1, 1.2915, 1.6681, 2.1544, 2.7826, 3.5738, 4.6416, 5.9948, 7.7426, 10]. logspace(0,2,10) gives [1, 1.6681, 2.7826, 4.6416, 7.7426, 12.9155, 21.5443, 35.9381, 59.9484, 100]. 10. F = logspace(0,3,21); 11. linspace(a,b,n) can be converted to a:step:b using a step = (b-a)/(n-1) 12. [1,2,4,5] produces a horizontal (row) vector with corresponding values. [2;3;6;10] produces a vertical (column) vector with corresponding values. 13. [G G] gives [1 2 4 5 1 2 4 5]. This is a horizontal concatenation operation. [1 G 4] gives [1 1 2 4 5 4]. Another horizontal concatenation operation. [1;H;4] gives a column vector with values [1;2;3;6;10;4]. Vertical concatenation. 14. L = [J K]; 15. L = [L J];

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16. ‘end’ allows you to easily access the last element without knowing the length of the vector. 17.
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E7_Lab02_Solutions_Fall_2010 - E7 Lab 02 Solutions 1. A...

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