Lecture21 - Chapter 4

Lecture21 - Chapter 4 - EE216 C ircuit Analysis I Le cture#...

Info iconThis preview shows pages 1–8. Sign up to view the full content.

View Full Document Right Arrow Icon
1 EE216 Circuit Analysis I Lecture # 21 – Chapter 4
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
2 Norton’s Equivalent Norton’s theorem simplifies a network in terms of currents instead of voltages For current analysis, Norton’s theorem can be used to reduce a network to a simple parallel circuit , with a current source and resistance
Background image of page 2
3 Norton’s Equivalent I N is the short-circuit current through terminals A and B. To find R N we must find V OC ; then Norton’s Resistance: R N = V OC /I N Alternatively , R N is the resistance across terminals A and B when all independent sources have been disabled.
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
4 Thevenin-Norton Conversion Norton from Thevenin R N = R TH I N = V TH /R TH Thevenin from Norton R TH = R N V TH = I N x R N
Background image of page 4
5 Thevenin’s Equivalent with Dependant Sources Determination of V TH remains same. Determination of R TH : Method 1: remains same, i.e. find I sc . Method 2: cannot be applied since dependant sources cannot be removed. Method 2 Alternate: disable independent current/voltage sources and apply a test voltage or current source . Usually, it is easiest to apply 1V or 1A test source.
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
6 Thevenin’s Equivalent with Dependant Sources (V TH ) V TH is voltage between EF is same as between AB 0 I 2 1 V 8 5 40 V X A A = - + - - 5 V 40 I A X - = V V V TH A 20 = =
Background image of page 6
7 Thevenin’s Equivalent with Dependant Sources (R TH thru I sc Method) I SC = 2I X + I X + 8 = 32 A (I X = 8 A) R Th = V Th /I SC = 20/32 = 0.625
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 8
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/21/2011 for the course EE 216 taught by Professor Azharruaf during the Spring '10 term at NUCES.

Page1 / 21

Lecture21 - Chapter 4 - EE216 C ircuit Analysis I Le cture#...

This preview shows document pages 1 - 8. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online