Lecture07 - Chapter 2, 3

Lecture07 - Chapter 2, 3 - EE216 C ircuit Analysis I Le...

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1 EE216 Circuit Analysis I Lecture # 7 – Chapter 2, 3
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2 Analysis of Circuits Containing Dependant Sources (1/3) Find voltage across the dependent current source THINK!!!
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3 Analysis of Circuits Containing Dependant Sources (2/3) Need to find V. We use KVL and Ohm’s Law, to write the voltage equation for the loop CEB: - V – (40I 1 )R 3 + V 3 - I 2 R 2 = 0 where I 2 is the current flowing through R 2 - V – 96I 1 + 10 - 0.5I 2 = 0 (1) 3 unknowns so, we need values for I 1 and I 2. Using KVL and Ohm’s Law, the voltage equation for the loop ACB: - V 1 + I 1 R 1 + V 2 + I 2 R 2 = 0 - 3 + 29.5I 1 + 0.5 + 0.5I 2 = 0 - 2.5 + 29.5I 1 + 0.5I 2 = 0 (2)
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4 Analysis of Circuits Containing Dependant Sources (3/3) Using KCL at node C: I 1 + 40I 1 = I 2 I 2 = 41I 1 (3) Substituting (3) in (2) - 2.5 + 29.5I 1 + 0.5(41I 1 ) = 0 I 1 = 50.0 μA (4) Substituting (4) and (3) in (1) - V – 96(50x10 -3 ) + 10 - 0.5(41 x 50x10 -3 ) = 0 V = 4.175 V
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5 Resistors in Series Consider a circuit with multiple resistors connected in series. Is there an
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This note was uploaded on 01/21/2011 for the course EE 216 taught by Professor Azharruaf during the Spring '10 term at NUCES.

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Lecture07 - Chapter 2, 3 - EE216 C ircuit Analysis I Le...

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