Lecture33 - Chapter 4,5,6

Lecture33 - Chapter 4,5,6 - EE216 C ircuit Analysis I Le...

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1 EE216 Circuit Analysis I Lecture # 33 – Chapter 4, 5, 6 Solved Examples & Problems
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More on Op-Amps – Why Op-Amps? 2 W K v P mV v v v o OP L o n p μ 4 . 6 16 320 2 ) ( = = = = = a) With Op-Amp in circuit: nW K v P mV v L NOP L L 400 16 80 16 48 16 320 2 ) ( = = = + × = b) With No Op-Amp in circuit: c) Power Ratio = 16
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More on Op-Amps – Why Op-Amps? 3 d) Op-Amp Advantages:
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Chapter 4 Example 1 4 0 10 6 5 2 8 25 . 2 = - + + - = b b o v v mA i
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Chapter 4 Example 2 5 W P R o 72 8 24 0 2 max = = =
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+ - 200 40 60 50 R o 100V 60I s I s The variable resistor R o in the circuit below is adjusted until it dissipates maximum power. a)Find the value of R o that satisfies this condition. b)Find the amount of power dissipated. Chapter 4 Example 3 6 W P R A I V V TH SC TH 8 . 0 20 * 4 ) 8 ( 20 4 . 0 8 2 max = - = = - = - =
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Prob 4.73) When a voltmeter is used to measure the voltage v e in figure below, it reads 7.5V. a) What is the resistance of the voltmeter?
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Lecture33 - Chapter 4,5,6 - EE216 C ircuit Analysis I Le...

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