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Unformatted text preview: ( x ) = sin( x ) x . 5b) If you multiply by 1 x , you nd ( x1 y ) = x1 sin( x ). 5c) y ( x ) = x (Si( x ) + c ) 6a) This is separable, and you nd y = 1 4 (2x ) 2 as long as y > 0. 6b) The solution hits 0 when x = 2, so your formula becomes doubtful then (since you probably divided by y to nd it). Look at the slope eld or the DE itself to see that the formula in part a) is incorrect beyond x = 2, and that y = 0 is the correct way to continue the solution into that region. 7...
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 Spring '07
 TERRELL,R
 Derivative

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