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# 1.6-3 - SECTION 1.6 Shear Stress and Strain Solution 1.6-3...

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Unformatted text preview: SECTION 1.6 Shear Stress and Strain Solution 1.6-3 NUMERiCAL DATA (b) BEARING STRESS ON [’lN FROM” FLANGE. PLATE P z 160 hips tip 2 2 in. “—* 1.3 In. 1r = I 111. Ubr 2 Uhr' : 20 ksi gm BEAIHNG STRESS ON PIN FROM GLJSSET l‘Li—XFE ' _P m v 4 - _P | —‘ W" T : "'w?“ 2 . (Trdl, 17d]? (fhg I m on, I 26.7 lisi (- \ 4 4 Flt T‘ =: [2.73131 ‘<— Problem 1.5-4 The inclined ladder AB supports :1 house painter ('82 kg) 111 C and the self weight {g = 36 N/n1) of the ladder itself. Eueh ladder rail (1‘, K 4 mm) is supported by a shoe (If. : 5 mm) which is; attached to the [adder rail by a bolt el‘diameter d], := 8 mm: (11) Find support reactions at A and B. {h} Find the resultant force in the shoe hell. :11 A; (c) Find maximum average shear (1-) and hearing (07,} stresses in the shne bolt ntA. _ 4' .3? Shoe lmlt atrl Kiri“? J _ I ./{/ 1‘ / . B t ,Z‘ ‘R t t ' t F“ 1 - Al. 1 4% if] .I‘ J "' Q} ‘"'““"““_‘““““T”"’ 1‘——'i S 5' “ ‘ M ”l 11:11.7 n1 5 1‘ 51.. - L—> I As‘téume en «Ii 1 '11 4 Seetinnuthase - 1 i t ‘ Selution 1.6-4 Nun-1151110511, DATA (3‘) Surrenrr REAC'I‘IUNS tr 2 4 mm [5 x 5 mm L : V/l—a 4» 119+ H: L x 71433 In dp I 8 mm P x 82kg(9.81m/53) a - w I L LAC x 5 352 m P I 804.42 N a + b N m h __ —, 7. 11=E.8m h=0.7m H=71n q = 36—— Lca — a + bL Lca — -1th m _ 1T] 33 ...
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