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# 7.3-11 - 588 CHAPTER 7 Analysis of Stress and Strain...

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Unformatted text preview: 588 CHAPTER 7 Analysis of Stress and Strain Problems 7.3-“ 03 = 2501) psi, 0'). 2 i020 psi, TX". 2 4301..) psi (a) Determine the principal stresses and Show them on 1.1 sketch of a properly oriented element. ' (h) Determine the maximum shear stresses anti associated normal stresses and Show them on :1 sketch of a properly oriented element. Solution 7.3—“ 0‘“. I 2500 psi :7". i 1021) psi TAT z —9011 psi Therefore, 1:010,” = —2“': 3‘ or. x 2925 psi sw (it) PRINCIPAL STRESSES ' _ j for tip: : 6—1.7“. tr; I 51):) psi <— -7} . itiill‘l( \ w) 27“ or— U", {13) Dalian-nix] SHEAR S'rnizssns tantZH ) x '—- H t z —-W Wk P I) "t , 1 ”32* n} ‘- f ”I m U) “ r: q- (a ‘ Turin = l (”Egg—i) 1 TH".- HPI = "3.2) , ‘ \. 3 - Up: = 90 ° + 9”. 01,3 = 64.71C . mm x 1155 psi 01+ ca- In w try _ » Hi] 2 0m — 45“ 0... a 4&3“ and 61 "—W T + “EM“ cm 1291):} '1‘ 70‘5”] (win) Ti 2 l 165 Psi +— 1 1953 = (-1“ -- 4-59 HQ 2 19.71” €le ”Zr '11 ”V (In: W ”1' 7 __ _ _ _ > ‘ (r3 2 m3“;- "1* - 2 ' eos (MP3) Trysm (ltijﬁ) '2 “ *1 103 P31 "W of“ + (7‘ [Tin-n : “WT”; (rum. = 1760 psi <— W. Problems 73-12 a}. Z 2151) kPa, a}. = 375 kPa. “r“. : v-lﬁ'tl 111311 (at Determine the principal stresses [ll’ltl show them on u sketch of it properly oriented elemenl. (bl Determine the maximum shear stresses and associated normal stresses and show them on a sketch of a properly oriented element. Solution 7.3-12 (Ix = 2150 kPa rry = 375 kPa Try = - 4601(1’3 _ Hm : W 13.703 {21) PRINCIPAL STRESSES 61,3 =‘- 91.13 ~1— 1},” HP: : 716.30C Mr W ”tr + Ur ”7r V 0-" ‘ man A‘ 0‘1 2 “W“; ‘1' — 1 e05 ('36,, ) + Twilllt (30!, i _ 21'”. 0'1. - cry, 3 3 ' ' ‘ inn(26,,) x U} _ [Ty Hm I we 2 _ ”J ”p m m _ (T‘- “r ~1—'—eos (Ellie) + rusin (265,3) 11 [T1 ‘ 'l ...
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