# 7 - -i"rublem 4 13 Th - . - 6 force F - 3 all! ’...

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Unformatted text preview: -i"rublem 4 13 Th - . - 6 force F - 3 all! ’ 1—0N-Ti‘ * - Ear I:Ile lune.» lb zero+ Wlaut is the sum ofmhveum Bum 13 lorces about point A? t e mumms Sﬁiﬂliﬂ j I II: T! ' ' ' ’ IL sums nl lhl: urn-us III the J: and 5' iJ'll'EﬂlilJﬂS Lqu I I "1+ Fleas-15" - F3 \$1530" : B 2-4:: sin-45° + Fagin 30" := U n F ~— " g l — ll! N and sulving yields F; = 53.0 N. F] _—_ 31." N. m uf - IhL muman about pn'mL A is 4:!” -' ° 2 5m 31] {8 m] + F3 c0545°£2 In] 2 4H} N-m is = \$1 . n N-m cmmlcreluekwise _._______._._.——-—-'—‘__ Problem 4.24 The tension in the euhle'is the same {m bmh sidee of line pulley. The sum M" the mnmems uhuut point A due In the 800-111 three and the forces exerted on the bar 11y the cable at B and C is gem. What is the Lenainn in the cable? Let T he the lenﬁiun in the cable. The :mm 01' the Solution: moments about A is E: MA -. mu in} + “r sin Ju’wu am — Lam 11mm“: = n Shh-111g yield: r" 30 ill —-'r-—ﬁ.(} in ._.. 4.37 Solution: Em. = — 8 B [290 kNIlfrlS m -— ~———{|4H kNJllé m «3200 J «330 } :; "3.36 MNm EMF = 3135 MN-m CW 4D In ...
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## This note was uploaded on 01/21/2011 for the course ENGR 200 taught by Professor Mullen during the Spring '08 term at Case Western.

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