7 - -i"rublem 4 13 Th - . - 6 force F - 3 all! ’...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: -i"rublem 4 13 Th - . - 6 force F - 3 all! ’ 1—0N-Ti‘ * - Ear I:Ile lune.» lb zero+ Wlaut is the sum ofmhveum Bum 13 lorces about point A? t e mumms Sfiifllifl j I II: T! ' ' ' ’ IL sums nl lhl: urn-us III the J: and 5' iJ'll'EfllilJflS Lqu I I "1+ Fleas-15" - F3 $1530" : B 2-4:: sin-45° + Fagin 30" := U n F ~— " g l — ll! N and sulving yields F; = 53.0 N. F] _—_ 31." N. m uf - IhL muman about pn'mL A is 4:!” -' ° 2 5m 31] {8 m] + F3 c0545°£2 In] 2 4H} N-m is = $1 . n N-m cmmlcreluekwise _._______._._.——-—-'—‘__ Problem 4.24 The tension in the euhle'is the same {m bmh sidee of line pulley. The sum M" the mnmems uhuut point A due In the 800-111 three and the forces exerted on the bar 11y the cable at B and C is gem. What is the Lenainn in the cable? Let T he the lenfiiun in the cable. The :mm 01' the Solution: moments about A is E: MA -. mu in} + “r sin Ju’wu am — Lam 11mm“: = n Shh-111g yield: r" 30 ill —-'r-—fi.(} in ._.. 4.37 Solution: Em. = — 8 B [290 kNIlfrlS m -— ~———{|4H kNJllé m «3200 J «330 } :; "3.36 MNm EMF = 3135 MN-m CW 4D In ...
View Full Document

This note was uploaded on 01/21/2011 for the course ENGR 200 taught by Professor Mullen during the Spring '08 term at Case Western.

Ask a homework question - tutors are online