Old_Finals_AnswersF08.doc
1
X
Y
R1
30
R2
20
M2
8
M1
10
A1
15
Station 1
Station 2
Station 3
Station 4
MGMT 46000: Answers to old final exams
F. 2008
Spring 2008: Answers/partial solutions
Question 2
Part A:
1.
What is the
cycle time (CT)
of
station 3
?
Capacity of station 3: 5 units/min.
CT = 12.0 sec/units.
2.
What is the
capacity
of the entire
process
in units per hour
?
Station 4 is the bottleneck. Process
Capacity = 240 units / hr.
3.
What is the
hourly
labor productivity of
this process
?
Productivity = (240 units / hr) / (5
workers) = 48 units / labor hour
4.
What is the
minimum throughput time TPT
of the complete process?
Explain
your answer.
Minimum TPT = 35 sec. Explanation must be added here.
Part B:
Flow rate = 5/6 min. Flow time = 12 min / customer.
The claim is not realistic.
Part C:
A.
How should we schedule the machine to maximize monthly production?
On odd numbered days start with J, do the set up change and produce M rest of the
day such that production of J and M is in the desired ratio. On even days, continue
with M and switch to J after the setup change.
B.
How many units of each product can we produce in 1 month? Verify that the numbers are in the
proper ratio desired.
Monthly production of J = 420 units. Monthly production of M = 840 units
Part D:
The
plant capacity of
22000 units of AA
means the plant is
open for 22 days.
43000 units of the
standard product will
need 43000/2000 =
21.5 days. Therefore
the plant capacity is adequate.
Question 3 [25 points]:
Part A:
u = 45000 / (12 * 25) = 150 units / day. H = 12 dollars per unit per year.
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 Fall '08
 panwalker
 Management, Harshad number, Trigraph, St., Brewery Distributor Wholesaler Retailer, Distributor Wholesaler Retailer, Ware St.

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