PartialKey_Test1-F08

PartialKey_Test1-F08 - MGMT 46000 Fall 2008 Test 1 Partial...

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PartialKey_Test1-F08.doc Question 2 [20 points] Consider the process shown. There is one worker per machine. Capacities given are in units per hour. At stage 1, there are two parallel machines (M1, M2) with capacities 8 and 10 respectively. At stage 2, the three parallel machines (P1, P2 and P3) have capacities 4, 4 and 8 respectively. Part A: [5 points] - What is the cycle time at each stage in minutes per unit? Cycle time at stage 1 = 60 / (8 + 10) = 3.33 [minutes / unit] Cycle time at stage 2 = 60 / (4 + 4 + 8) = 3.75 [minutes / unit] Part B: [4 points] - What is the process productivity? Bottleneck is stage 2 with capacity = 16 units per hour Productivity = 16 /5 = 3.2 units per labor per hour. Part C: [3 points] - What is minimum TPT? Write brief explanation. Faster machine at stage 1 is M2 (takes 6 minutes), fastest machine at stage 3 is P3 (takes 7.5 minutes). So, minimum TPT = (6 + 7.5) = 13.5 min. Part D: [8 points] - You want to increase the capacity of the system and you have the following two choices (you must select one of these choices). i. Replace P3 with machine P4 requiring 5 minutes per job. Replacement cost: $1000 ii. Add another machine P5 (requiring 10 minutes to process each job) at a stage 2: Cost: $1200 Which choice will you select? Why? Choice i: Capacity of P4 is 12. Stage 2 capacity = 4 +4+12 = 20 units per hour Choice ii: Capacity of P5 is 6. Stage 2 capacity = 4+4+8+6 = 22 units per hour For both choices, the bottleneck is shifted to stage 1. So choose cheaper alternative
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This note was uploaded on 01/21/2011 for the course MGMT 46000 taught by Professor Panwalker during the Fall '08 term at Purdue.

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PartialKey_Test1-F08 - MGMT 46000 Fall 2008 Test 1 Partial...

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