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Unformatted text preview: ( x − μ ) 2 2 σ 2 . Then du = 1 σ 2 ( x − μ ) dx and your Frst integral now will be equal to σ √ 2 π ° e − u du. This can be easily solved and you then only need to get the correct integral bounds for u and then it should be fairly obvious that this integral is zero. 1...
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This note was uploaded on 01/21/2011 for the course MATH 3C taught by Professor Schonmann during the Spring '07 term at UCLA.
- Spring '07