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Gas Laws and Thermochemistry Worksheet - Key

# Gas Laws and Thermochemistry Worksheet - Key - 6A5 LAWS é...

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Unformatted text preview: 6A5 LAWS é THERMOCHEMISTRV WORKSHEET GENERAL CHEMISTRY 1A. Chapter 5 - Gas Laws , 1. Calculate the pressure by the following conversions: to) 2.25otmtotorr- 3. 35a 760m,“ Huff -£“H 7003 +ori/ lakﬁ [ l ”'ij (b)1.38atmtommHg 1.315Wll3-[Dgxlbgmmll (c) 866 tor-r to mm Hg iiiat. Min lit? :- l‘ﬁlo mm ”3 l l 1% 2. Calculate the final pressure of a sample of gas that is expanded to 1.50 L at constant temperature from 955 mL at 1.17 atm. What law is this? Derive the law from the ideal gas law? Pv= W P; = PM FIELD“ ﬂ ——-——» P‘ as: V9, V P; = Q.I'74lm)(o.0lE§,V VaszoL P =1. Canshni) .—.> 30am" ”Law (Iggy) P}: 7: v 3‘ ' 9K Mimi?- Pv= Gonéhné . ,5 mnslvznl' PIVi : 91V; =7 Wits. it“) A5 V T Pl' -Carrett / 3. Calculate the initial volume at 419K of a sample of gas that is changed to 4.22 L by cooling to 317 K at constant pressure. What law is this? Derive this law from the ideal gas law. in; _ #v I — PV— an‘ Vi = :2; :1) chltl’lls La” _ If; V , n :‘t‘ V- T( E113) - V T (Constanlr) 3* Chm 5‘5 Lat} ' - 'ﬁ 3 Constanlt ) R = an“? ., _ - eons mi - = tanslarIt ' 4. Ammonia burns in oxygen gas to form nitrogen monoxide and water vapor. How many volumes of NO are obtained from one volume of ammonia at the same temperature and pressure? What law is this? Derive . . W this law from the Ideal gas law. V: KYL 1V0lumﬁ Nllb :1 QM“? ““3 2M, (3) +106. agnom 451410“) v: Eonslznt’ n snag. Hmal N145; a mu; No 5/4” i : ionshnl' than l ‘10”me N0 Hm: “ - ““ 3(3) l’ 57043) 9 410(3) 4» (111166) Vi if Checlf: V : IL --' 2.3 v ”U: Wii7 2 V at - PW La M n‘” 4% ”W If“ HMS“ PAGE10F4 am} Volume 5 6A5 LAWS 6i THERMOCHEMISTRV WORKSHEET GENERAL CHEMISTRY 1A 5. Calculate the final volume of a sample of gas initially occupying, 264 mL at STP after its pressure is increaSed to 1.63 atm and its temperature is increased to 15°C. Derive the equation you will uSe from the 'dealg‘” km" W = n KT Ll" .-. canslanlr P V1: {2‘36 Waitibdlajx V 1*- :i‘iliemu V3 :1: V: nth" T (213V)(].{,3«i,0 1-, «w 0°C =etaK T, a ls‘c; 233K "‘5‘ '- if; ”V39; fl= [elm P351415 nth. V=1Lnﬂ) - Tl #1:; n: Constant , ii salwels eons-lan'l' u: g: (cmslahl' ) 5 V3 ; 1% i a 6. What is the molar- mass ofagas if294goccupie5138Lat220 atm and 12°C? “M' i 1 émﬁﬂﬁssy) : 54-; 0- Howls moi C) 00 8200::fmgfﬂ “n— m - 3 7139.! 0.5:130lml N- nKT ﬂ. 7. One out of ten molecules in a room is nitrogen gas. If the total preSSure is 760 torr, what is the partial pressure of nitrogen gas? What law is this? PE; : xii; (91ml) 3) Dalhn’s law a? Parhhﬂ Pmrc PN “we” _ r/ PAHWLI szssure :: Hal Galilean x fulﬁl ﬁrm“ m) N; Na, 6. A piece of Sodium metal reacts completely with water: 2Na (5) + area (I) —+ ZNaOH (aq) + H2 (9). The hydrogen gas generated is collected over water at 250°C. The volume of the gas is 246 mL measured at 1.00 atm. Calculate the number of grams of sodium usad in the reaction given the vapor pressure of water at 259°C is 0.0313 atm). 4 We Cannot use ‘ch ideal gas law on Sad-gum , lair, ii is trial on gas" at 53 @04le mi ‘Hic mobs oé 3a; lint Na produuol, Wt Com use slog; in Find ou'l' “”5 W95 #70 glam; Nv» tl‘vil- magical —+ m auteunl mt ll; prisms is thc amouni of NA“) 'l'lnwl' mm 4 "no tow: Pressure is mini Ni‘lh lilo (9) 1"“;(5), Niel in Fails PM ParhUL Pmﬁuﬁb ll; 3 fTa'IAL 'Uﬁfp/ Pam“, ﬂap WV»«~”‘~—- . ha: W0 030M. -' 0.0‘§l§o\+n~ : 0.0ll11qlm' 51.15 “ﬁaw 2M: 22.!” N3, moi/ll" 1M0» - P‘J; hilt“ => Vi= EX ‘ PH; V143,. eiv‘ﬁbﬁafﬁlﬁo._1%g) 1' l r 111’ L ”a (a..o?bb%)(zqy) =_ PA6E20F4 6A5 LAWS 6i THERMOCHEMISTR'V WORKSHEET GENERAL CHEMISTRV 1.4 Chapter 6 — Thermodynamics 1. Consider these changes: . . (a) Hg (l)—)Hg (9:9 _A llama lurnﬁ into 413.413 1 Sqﬁl-un clots mrl‘ on surwundmss r. expahsmn (b) 302(9)~>202(1)A gas turns mtg a. liar dx'. surmndings all. worK Magellan: “WPWSSi‘m (c) CuSO4o5H20(s)>Cu504(s)+5H20(9) : Snilol turns {n+9 gas 3 ”51““ on 811"”,de (d) H2(9) "‘ F2(9) —> ZHF (g) l l mol ll; l- lle F; =7 1mnl ”—r lino] -' No worK Aline At constant pressure, in which of these reactions is work done by the system on the surroundings? By the surroundings on the system? In which of them is no work done? 5e: dime . Z. A Sample of nitrogen gas expands in volume from 1.6 L to 5.4 L at constant pressure. Calculate the work done in Joules if the gas expands: (a) Against a vacuum (h) Against a constant pressure of 0.80 atm (c) Explain what is happening from the systems point of view for each expansion L“) N'- 'PDV i Mums}? A Wcaam¥ there is N: ulnar/dc, in Vail/lint, bll‘o) W50 VFmalll - ‘41»th (b) w= 43M = w; (a {yon-lm)(5“ll_' 19L) N’m - a. 0 mg m. 53' 3. am \$V\$l£ln alws snort on the l lM Q Surroundings- 945nm 3 Calculate the work done when 50 0 g of tin dissolves in excass acid at 1.00 atm and 25°C: Vim 5n (s) + ZH" (aq) —+ Snz” (aq) + H; (g) P V: n [QT 56.49 IMK' lmolll-‘Vzolelnail-l; VF‘ “ST }lﬂ ll?! .bqé/ I W5“. Ajallfl llu l-ll Masures how much Sn, mad—{A_ VF' lo 5i— l.(Doat)~C / Tl‘a mlnal VUlumL ll}; = 0L ) ‘l'lmrt was 7‘qu -— - P bV: -10de (nun *0L) 4. Aluminum metal reacts with chlorine with a spectacular display of sparks! How much heat in U is released on reaction of 5.00 9 Al? ZAI (s) + SCI; (9) -+ ZAICI; (3) AH.“ = 4408.4 kJ’ 5.0a MM HOEAKJ’ ; at..ng 2M] BEnfamslm VF >VI lal KT lud‘l was. Khaki l‘lf‘ll erasai =€XD‘l’lUrmle rm PAGE 3 OF 4 GAS LAWS 6: WERMOCHEMISTRY WORKSHEET GENERAL CHEMISTRV '1A 5. Consider the reaction: sz0 (g) —> 2H; (9) + Oz (9) AHM = + 483.6 kJ' If 2.0 moles of H20 (9) are converted to H2 (9) and 02 (9) against a pressure of 1.0 atm at 25°C, what is AEfor‘this reaction; “Final = 2M1“; 4. lrrui 0.; = 5mm? 5 Pf ‘ Ag *0? itiniiriim ‘-’» L F'Mii H30 i am! iani' ., mi +DPV ”9 ' DE I/K 15E -. ‘Ll sa, boo)" 1- (lmﬁifi'ii‘l T/Wﬂlﬂg AE - mi wriﬂt) W. M + w- Wm 6. A piece of silver of mass 362 grams has a heat capacity of 87.7 37°C. What is the Specific heat of the silver? ”(A (11‘3“;th = C, :- ‘E'i-“l j/ut 9i‘E‘L‘p‘Cl‘ii‘l4r "; C, K "”59 obieci -" (31-737-c)(5"2'5) ‘ 5 7. Mothballs are composed primarily of naphthalene CmHa. When 1.025 g of naphthalene is burned in a bomb calorimeter, the temperature riSes from 245°C to 32.33°C. Find AEWM CmHa for the combustion of naphthalene. The heat capacity of the calorimeter is 5.11 kJ/“C. Write an equation for the reaction. , (in, ”3 +19% ﬁIOCOJCﬁ quite «their 68, e C, AT . 6r 0L bomb calorime‘ie'i AE .~. WW . % Spay ‘ 5' H KI 32 ‘33-), 2 ‘ \9 .. Ag: % + ~va J AV :0; tag/)( ' I ”5% i . Hm} maf» l2 [Miami Earn (G’SWF ”9'0 K3— DE= \/ biwc to suit Nil (11’ W 01! "3) qrrxheﬂbibﬂiifjwmd (l) C5H12(l)+802(g)-+5€Og(g)+6HgO (g) AH=-3508.8 kJ / 1.0:: l? we“, ”'3 (z) C(s)+02[q)-*COE(9} AH: - 393.5 kJ - - ”Mg (3 ) 2H2 (g) + 02 (g) "' 2H20 (9) AH = ' 483.5 kJ r. a a V i 7.4! I“ I _ :‘h ' k) Eel/(I3 lieu . 5m + We (1.-“ +9 afﬁx/QM", ,_ .. :3 mo _______._ / .1 '> t, n. 9”.» ”5,034, K' Db:— §.le )UD :3 D / I ' a. 'i 50 Hall .4 c H f w ”1/6 g 2 ”3’09 EW‘UJ" 'l‘iW'rtasbﬁ-t “—leibfi w c anus-’5'. . ‘ Mi; Eagwim) angina) «———«“—————-7 new L-ibiien PAGE4OF4 :1 ,w0(9'1t_3" _.—v—-*———-_.___. ...
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