ch10 2_Part3 - GENERAL CHEMISTRY CHAPTER 10: PART II...

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GENERAL CHEMISTRY CHAPTER 10: PART II – CHEMICAL BONDING PAGE 11 OF 15 Consider the He 2 Molecule 2 e - will be in the low-energy bonding orbital, and 2 e - will be in the high-energy anti-bonding orbital The result is that the electron energies are, on average, no lower than they would have been had bonding not occurred Consider the Li 2 Molecule We are only going to look at the valence electrons – WHY? Any filled energy level will generate “filled” bonding and anti- bonding MO’s only consider valence e - 2 e - will be in the low-energy bonding orbital, and no electrons will be in the high-energy anti-bonding orbital The result is that the electron energies are, on average, lower than they would have been had bonding not occurred Since more electrons are in bonding orbitals than are in anti-bonding orbitals, net bonding interaction Bond order = (2-0)/2 = 1 Consider the Be 2 Molecule 2 e - will be in the low-energy bonding orbital, and 2 e - will be in the high-energy anti-bonding orbital The result is that the electron energies are, on average, no lower than they would have been had bonding not occurred Bond order = (2-2)/2 = 0 Molecule does not exist
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This note was uploaded on 01/21/2011 for the course PHYS 4A 60865 taught by Professor L. oldewurtel during the Fall '09 term at Irvine Valley College.

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ch10 2_Part3 - GENERAL CHEMISTRY CHAPTER 10: PART II...

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