ps3solnsF06 - %Engineering 6 Fall 2006 Problem 3.1...

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%(Triangle problem) %Suppress extra lines in output and clear command window and variables format compact ; clc; clear; %Note: There are several ways to solve this problem. We use % the law of cosines below. %Initialize variables (sides of triangle, angles b and c in radians) sideDE = 24; sideEF = 13; b_degs = 38; %We only need b in degrees for the calculations below c_rads = 48*pi/180; %Use law of cosines to find the length DF sideDF = sqrt(sideEF^2 + sideDE^2 - 2*sideEF*sideDE*cos(c_rads)); %Use DF, the law of cosines, and the acos function to find %the angle a in degrees a_degs = 180/pi*acos((sideEF^2 - sideDE^2 - sideDF^2)/(-2*sideDE*sideDF)); %Calculate angle d in degrees(where a+d+(180-b)=180, or d=b-a) d_degs = b_degs - a_degs; %Display results fprintf( 'For the given triangle:\n' ); fprintf( 'The length DF is %.1f meters.\n' ,sideDF); fprintf( 'The angle a is %.1f degrees.\n' ,a_degs); fprintf( 'The angle d is %.1f degrees.\n' ,d_degs); Displayed results: For the given triangle: The length DF is 18.1 meters. The angle a is 32.3 degrees.
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This note was uploaded on 01/22/2011 for the course ENG 006 taught by Professor Lagerstrom during the Fall '06 term at UC Davis.

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ps3solnsF06 - %Engineering 6 Fall 2006 Problem 3.1...

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