A student whose normal weight is 500 newtons stands on a scale in an elevator and records the scale
reading as a function of time.
The data are shown in the graph above. At time t = 0, the elevator is at
displacement x = 0 with velocity v = 0. Assume that the positive directions for displacement, velocity,
and acceleration are upward.
a.
On the diagram to the right, draw and label all of the forces on the
student at t = 8 seconds.
b.
Calculate the acceleration a of the elevator for each 5second interval.
i. Indicate your results by completing the following table.
Time Interval (s)
05
510
1015
1520
a (ms
2
)
ii. Plot the acceleration as a function of time on the following graph.
c.
Determine the velocity v of the elevator at the end of each 5second interval.
i. Indicate your results by completing the following table.
Time
(s)
05
510
1015
1520
v (m s)
ii. Plot the velocity as a function of time on the following graph.
d.
Determine the displacement x of the elevator above the starting point at the end of each 5second
interval.
i. Indicate your results by completing the following table.
1993
107
107 cont
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Time
(s)
05
510
1015
1520
x (m)
ii. Plot the displacement as a function of time on the following graph.
A charge Q
1
= 1.6 x 10
6
coulomb is fixed on the xaxis at +4.0 meters, and a charge Q
2
= + 9 x 10
6
coulomb is fixed on the yaxis at + 3.0 meters, as shown on the diagram above.
a.
i. Calculate the magnitude of the electric field E
1
at the origin O due to charge Q
1
ii. Calculate the magnitude of the electric field E
2
at the origin O due to charge Q
2
.
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 Spring '10
 Wei
 Light, Magnetic Field, 8 seconds, 4.0 meters, 9 hertz

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