1993 Free Response - 1993 107 A student whose normal weight...

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A student whose normal weight is 500 newtons stands on a scale in an elevator and records the scale reading as a function of time. The data are shown in the graph above. At time t = 0, the elevator is at displacement x = 0 with velocity v = 0. Assume that the positive directions for displacement, velocity, and acceleration are upward. a. On the diagram to the right, draw and label all of the forces on the student at t = 8 seconds. b. Calculate the acceleration a of the elevator for each 5-second interval. i. Indicate your results by completing the following table. Time Interval (s) 0-5 5-10 10-15 15-20 a (m|s 2 ) ii. Plot the acceleration as a function of time on the following graph. c. Determine the velocity v of the elevator at the end of each 5-second interval. i. Indicate your results by completing the following table. Time (s) 0-5 5-10 10-15 15-20 v (m| s) ii. Plot the velocity as a function of time on the following graph. d. Determine the displacement x of the elevator above the starting point at the end of each 5-second interval. i. Indicate your results by completing the following table. 1993 107 107 cont
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Time (s) 0-5 5-10 10-15 15-20 x (m) ii. Plot the displacement as a function of time on the following graph. A charge Q 1 = -1.6 x 10 -6 coulomb is fixed on the x-axis at +4.0 meters, and a charge Q 2 = + 9 x 10 -6 coulomb is fixed on the y-axis at + 3.0 meters, as shown on the diagram above. a.
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This note was uploaded on 01/22/2011 for the course PHY 201 taught by Professor Wei during the Spring '10 term at Sam Houston State University.

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1993 Free Response - 1993 107 A student whose normal weight...

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