calc 2 wa 2

# calc 2 wa 2 - 2.2#40 limx-3(2x 5 2-3 5=-6 5=-1 = L Given >0...

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2.2 #40. →- ( + ) limx 3 2x 5 - + = - + =- = 2 3 5 6 5 1 L > : Given ε 0 | (2x+5)- -1 | < ε | 2x+6 | < = ε δ Hence, let = ε δ Hence, if < + < = 0 |2x 6| δ ε , you have | 2x+6 | < ε | (2x+5)- -1 | < ε ( ) - < |f x L| ε 2.3 #42. = - L 3 = - hx x2 3xx = - xx 3x = - = x 3 gx agrees at all points except x= 0 #46. →- - - + limx 12x2 x 3x 1 = ( + )( - ) + x 1 2x 3 x 1 = →- - limx 12x 3 = -5 = L agrees at all points except x= -1 #52. - - limx 33 xx2 9 = - - (- - ) limx 33 x3 x 3 x = - - limx 31 3 x = - 16 #58. + - - limx 3x 1 2x 3 = + - - + + + + = ( + )- - ( + + )= - - ( + + )= ( + + )= x 1 2x 3 x 1 2x 1 2 x 1 4x 3 x 1 2 x 3x 3 x 1 2 1 x 1 2 = 14 L #60. → ( + )-( ) limx 0 1x 4 14 x #62. ? #72. limθ 0cosθtanθθ = tanθ sinθcosθ ( ) = = = limθ 0cosθ sinθ θ cosθ sinθθ 1 L #78. I need to review trig again. This one really messed me up.

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#82. ? #108. = - + st 16t2 1000 lim - ( ) - t asa s t a t = - = - + st 1000 16t2 1000 - = = . 200016 t 11 18 sec 2.4 #4. a)
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## This note was uploaded on 01/22/2011 for the course MAT 231 taught by Professor Thurber during the Winter '09 term at Thomas Edison State.

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calc 2 wa 2 - 2.2#40 limx-3(2x 5 2-3 5=-6 5=-1 = L Given >0...

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